To graph the equation, plot a few points then connect then with a line.
f(x) = 440 - 55x
Plug in numbers for x to get the y value.
f(0) = 440
f(1) = 385
f(2) = 330
f(3) = 275
f(4) = 220
f(5) = 165
So when you graph these points, the y intercept is y = 440 because the graph crosses the y axis at (0, 440).
The x intercept is where the graph crosses the x axis. This happens when y = 0.
0 = 440 - 55x. Solve for x.
55x = 440
x = 8
So the x intercept is x = 8
Answer:
21
Step-by-step explanation:
![\left[\begin{array}{cc}5&9\\-6&9\end{array}\right] +6\left[\begin{array}{cc}-5&2\\7&8\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7D5%269%5C%5C-6%269%5Cend%7Barray%7D%5Cright%5D%20%2B6%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7D-5%262%5C%5C7%268%5Cend%7Barray%7D%5Cright%5D)
Multiply the second matrix by 6.
![\left[\begin{array}{cc}5&9\\-6&9\end{array}\right] +\left[\begin{array}{cc}-30&12\\42&48\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7D5%269%5C%5C-6%269%5Cend%7Barray%7D%5Cright%5D%20%2B%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7D-30%2612%5C%5C42%2648%5Cend%7Barray%7D%5Cright%5D)
Add the corresponding cells in each matrix.
![\left[\begin{array}{cc}5-30&9+12\\-6+42&9+48\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7D5-30%269%2B12%5C%5C-6%2B42%269%2B48%5Cend%7Barray%7D%5Cright%5D)
![\left[\begin{array}{cc}-25&21\\36&57\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7D-25%2621%5C%5C36%2657%5Cend%7Barray%7D%5Cright%5D)
I believe the problem asks for the slope. This problem can be done by putting <span>y=x^2e^5x into slope intercept form. However, the issue is that there is the variable "e", which does not match the slope intercept formula, y=mx+b. Long explanation short, the slope is </span>
13 1/4 is the answer
9 7/8 + 3 3/8
12 10/8
13 2/8
13 1/4 (simplified)
1 1/4 + 1/2 + 3/4 =
5/4 + 1/2 + 3/4 =
5/4 + 2/4 + 3/4 =
10/4 = 2 1/2 (or 2.5) oz's <
