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mr_godi [17]
3 years ago
13

Please help me find X ( I figured out the first part

Mathematics
1 answer:
zaharov [31]3 years ago
8 0

Answer:

128

Step-by-step explanation:

X is a corresponding parallel angle, the angle opposite it which is 128 would be the same because they are parallel angles.

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Determine if the following lines are parallel (never intersect), perpendicular (intersect at a 90 degree angle), intersecting (i
mihalych1998 [28]

Answer:


These lines are perpendicular.

Step-by-step explanation:

Put both equations in the slope intercept form of a line.

y = -6x - 8  This is already in the slope intercept form for a line

-x + 6y = 12  Add x to both sides of the equation

6y = x + 12  Divide through the whole equation by 6

y = 1/6x +2  

Now we compare the two slopes of -6 and 1/6.  They are negative reciprocals of each other.  That means that the line are perpendicular.

7 0
2 years ago
I need help answering this one
aniked [119]
I already a seed you when you asked this the first time. The answer is 3.
You multiply both sides by 50 and then you get this
(In the picture)
3 0
3 years ago
Can someone solve this its probably easy but i dont know
Rzqust [24]

Answer:

Step-by-step explanation:

A={26,30,32,44,48}

B={22,26,34}

A∩B=26

number of elements=1

elements in ξ are {22,24,26,28,30,32,34,36,38,40,42,44,46,48}

number of elements  in ξ=14

P(A∩B)=1/14

I can't draw venn diagram but i give hint

A={30,32,44,48}+{26}

B={22,34}+{26}

A∩B={26}

6 0
3 years ago
Which expression should you simplify to find the 90% confidence interval,
bogdanovich [222]

Answer:

0.45 - 1.96\sqrt{\frac{0.45(1-0.45)}{36}}=0.2870.45 + 1.96\sqrt{\frac{0.45(1-0.45)}{36}}=0.613

we can conclude at 95% of confidence that the true proportion of interest for this case is between 0.287 and 0.613

Step-by-step explanation:

The estimated proportion of interest is \hat p=0.45

We need to find a critical value for the confidence interval using the normla standard distributon. For this case we have 95% of confidence, then the significance level would be given by \alpha=1-0.95=0.05 and \alpha/2 =0.025.

And the critical value is:z_{\alpha/2}=-1.96, z_{1-\alpha/2}=1.96

The confidence interval for the true population proportion is interest is given by this formula:  

\hat p \pm z_{\alpha/2}\sqrt{\frac{\hat p (1-\hat p)}{n}}

Replacing the values provided we got:

0.45 - 1.96\sqrt{\frac{0.45(1-0.45)}{36}}=0.287\\\\0.45 + 1.96\sqrt{\frac{0.45(1-0.45)}{36}}=0.613

And we can conclude at 95% of confidence that the true proportion of interest for this case is between 0.287 and 0.613

5 0
3 years ago
Hola busco nva si quieres ​
LenKa [72]

Answer:

buena suerte ojala encuentres

7 0
3 years ago
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