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qwelly [4]
3 years ago
13

Resistors R1, R2, and R3 are connected in parallel. R1 is 68 ohm and R2 is 93 ohm. The equivalent resistance of the parallel com

bination is 26-ohm. What is the resistance of R3?
please show work! :)
Physics
2 answers:
Pachacha [2.7K]3 years ago
8 0

Answer:

77 Ω

Explanation:

For resistors in parallel:

1/R = 1/R₁ + 1/R₂ + 1/R₃

1/26 = 1/68 + 1/93 + 1/R₃

1/R₃ = 0.013

R₃ = 77

The resistance of R₃ is 77 Ω.

dsp733 years ago
8 0

Answer:

R3=76.9 ohm

Explanation:

Hello

the  equivalent resistance is given by the expression:

\frac{1}{R_{eq} } =\frac{1}{R_{1} } +\frac{1}{R_{2} }+\frac{1}{R_{3} }+...\frac{1}{R_{n} }

we have R1=68 ohm, R=93 ohm, Rt=26 and the resistor R3 is unknown.

\frac{1}{26 } =\frac{1}{68 } +\frac{1}{93} }+\frac{1}{R_{3} }\\\frac{1}{26 } =\frac{((93*R_{3})+(68*R_{3})+(68*93)) }{68*93*R_{3} }\\26((93*R_{3})+(68*R_{3})+(68*93)) }={68*93*R_{3} }\\\\\\2418R_{3}+1768R_{3}+164424=6324R_{3}\\R_{3}(2418+1768-6324)=164424\\-2138R_{3}=-164424\\R_{3}=\frac{164424}{2138}\\ R_{3}=76.9 ohm

Have a great day.

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