The height at t seconds after launch is
s(t) = - 16t² + V₀t
where V₀ = initial launch velocity.
Part a:
When s = 192 ft, and V₀ = 112 ft/s, then
-16t² + 112t = 192
16t² - 112t + 192 = 0
t² - 7t + 12 = 0
(t - 3)(t - 4) = 0
t = 3 s, or t = 4 s
The projectile reaches a height of 192 ft at 3 s on the way up, and at 4 s on the way down.
Part b:
When the projectile reaches the ground, s = 0.
Therefore
-16t² + 112t = 0
-16t(t - 7) = 0
t = 0 or t = 7 s
When t=0, the projectile is launched.
When t = 7 s, the projectile returns to the ground.
Answer: 7 s
Answer:
#14 - t = for each t-shirt(s) sold / h = hour(s) worked
8h + 0.50t
#15 - d = for hot dog(s) sold / h = hour(s) worked
8.50h + 0.35d
Is this what you needed?
Point A is exactly in the middle...it is halfway between 0 and 1...so it is 1/2 or 0.5
2x + (x+9) = 90
3x + 9= 90
3x= 81
x= 27
Now plug in 27 to (x+9)
27+9= 36
Final Answer = 36