Question

120 ≤ 12 k + 29 need help

Answer 1

The answer is $k$ ≥ $\frac{91}{12}$

First, you must flip the equation

$12k+29$ ≥ $120$

Then, you must subtract 29 on both sides

$12k$ ≥ $91$

Finally, divide both sides by 12

$k$ ≥ $\frac{91}{12}$