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3 years ago

If the force of gravity increases, which measurement will change and how?

1 answer:

4 0

Answer: If the force of gravity increases than the distance between the both masses will decrease that is both masses will come closer.

Explanation:

The expression of the force of the gravity is given by:

$F=G\frac{Mm}{r^2}$

G = Gravitational constant

M,m = masses of the both the objects

r = distance between the both the masses

From the expression we can see that force of gravity is inversely related to the square of the distance 'r' between the both masses.

$F\propto \frac{1}{r^2}$

If the force of gravity increases than the distance between the both masses will decrease that is both masses will come closer. The value of 'r' will get reduced.

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PLEASE HELP!!! The gold foil Rutherford used in his scattering experiment had a thickness of approximately 4×10−3 mm . If a sing

Ilya [14]

Answer:

16 atoms thick

Explanation:

4*10-3= 37

2.9*10-8=21

37-21=16

3 0

3 years ago

Read 2 more answers

Three gases (8.00 g of methane, CH4, 18.0 g of ethane, C2H6, and an unknown amount of propane, C3H8) were added to the same 10.0

klemol [59]

Answer:

Partial pressure of methane: 1.18 atm

Partial pressure of ethane: 1.45 atm

Partial pressure of propane: 2.35 atm

Explanation:

Let the total moles of gases in a container be n.

Total pressure of the gases in a container =P = 5.0 atm

Temperature of the gases in a container =T = 23°C = 296.15 K

Volume of the container = V = 10.0 L

$PV=nRT$ (Ideal gas equation)

$n=\frac{PV}{RT}=\frac{5.0 atm\times 10.0 L}{0.0821 atm L/mol K\times 296.15 K}=2.0564 mol$

Moles of methane gas = $n_1=\frac{8.00 g}{16.04 g/mol}=0.4878 mol$

Moles of ethane gas = $n_2=\frac{18.00 g}{30.07 g/mol}=0.5986 mol$

Moles of propane gas = $n_3=?$

$n=n_1+n_2+n_3$

$n_3=n-n_1-n_2=2.0564 mol-0.4878 mol-0.5986 mol= 0.9700 mol$

Partial pressure of all the gases can be calculated by using Raoult's law:

$p_i=P\times \chi_i$

$p_i$ = partial pressure of 'i' component.

$\chi_1$ = mole fraction of 'i' component in mixture

P = total pressure of the mixture

Partial pressure of methane:

$p_1=P\times \chi_1=P\times \frac{n_1}{n_1+n+2+n_3}=P\times \frac{n_1}{n}$

$p_1=5.00 atm\times \frac{0.4878 mol}{2.0564 mol}=1.18 atm$

Partial pressure of ethane:

$p_2=P\times \chi_2=P\times \frac{n_2}{n_1+n+2+n_3}=P\times \frac{n_2}{n}$

$p_2=5.00 atm\times \frac{0.5986 mol}{2.0564 mol}=1.45 atm$

Partial pressure of propane:

$p_3=P\times \chi_3=P\times \frac{n_3}{n_1+n+2+n_3}=P\times \frac{n_3}{n}$

$p_3=5.00 atm\times \frac{0.9700 mol}{2.0564 mol}=2.35 atm$

5 0

4 years ago

One important drawback of the use of hcfcs as a replacement for cfcs is that hcfcs.

maw [93]

One important drawback of the use of hcfcs as a replacement for cfcs is that hcfcs are more potent greenhouse gases.

<h3>What is hcfcs?</h3>

HCFCs is an acronym for hydrochlorofluorocarbons (HCFCs).

Thye are fully or partly halogenated hydrocarbons that contain carbon (C), hydrogen (H), chlorine (Cl), derived from alkane family.

CFCs is an acronym for Chlorofluorocarbons (CFCs), derived from alkane family like hydrochlorofluorocarbons.

<h3>Disadvantage of hcfcs over cfcs</h3>

One important drawback of the use of hcfcs as a replacement for cfcs is that hcfcs are more potent greenhouse gases.

Learn more about hcfcs and cfcs here: brainly.com/question/15885478

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2 years ago

What is the definition of Amplitude?

katen-ka-za [31]

Answer:

the maximum extent of a vibration or oscillation, measured from the position of equilibrium.

Explanation:physics

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3 years ago

What is the difference between cells, tissues and organs

k0ka [10]

Answer:

A group of cells working together is defined as a tissue and several tissues working together comprise an organ.

Explanation:

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4 years ago