Answer:
Because of the breeds
Explanation:
Like in humans, the dogs belong to the same scientific group, but through the passing of time, there has been some changes in their DNA, slightly differences that make the size, the hair, and another traits to be different.
In humans all the "breeds" suffer the same changes, that is the reason that spite we are homo sapiens, there are different groups of humans as the oriental, Caucasian, etc.
Answer:
Using the molarity of the solution
Explanation:
The concentration of the two solutions can be compared by the use of the number of moles of solute present in each of the solutions. The solution with a higher molarity will be concentrated while the solution with a lower molarity will be dilute.
Answer:
Avogadro's number
Explanation:
Avogadro number:
The given problem will solve by using Avogadro number.
It is the number of atoms , ions and molecules in one gram atom of element, one gram molecules of compound and one gram ions of a substance.
The number 6.022 × 10²³ is called Avogadro number.
It means 1 mole of any substance contain 6.022 × 10²³ number of representative particles.
For example,
18 g of water = 1 mole = 6.022 × 10²³ molecules of water
35.45 g Cl⁻ = 1mole = 6.022 × 10²³ Cl⁻ ions
1.008 g of hydrogen = 1 mole = 6.022 × 10²³ atoms of hydrogen
Answer:
C₃H₈(g) + 6 H₂O(g) ⇒ + 10 H₂(g) + 3 CO₂(g)
Explanation:
Propane can be turned into hydrogen by the two-step reforming process.
In the first step, propane and water react to form carbon monoxide and hydrogen. The balanced chemical equation is:
C₃H₈(g) + 3 H₂O(g) ⇒ 3 CO(g) + 7 H₂(g)
In the second step, carbon monoxide and water react to form hydrogen and carbon dioxide. The balanced chemical equation is:
CO(g) + H₂O(g) ⇒ H₂(g) + CO₂(g)
In order to get the net chemical equation for the overall process, we have to multiply the second step by 3 and add it to the first step. Then, we cancel what is repeated.
C₃H₈(g) + 3 H₂O(g) + 3 CO(g) + 3 H₂O(g) ⇒ 3 CO(g) + 7 H₂(g) + 3 H₂(g) + 3 CO₂(g)
C₃H₈(g) + 6 H₂O(g) ⇒ + 10 H₂(g) + 3 CO₂(g)