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3 years ago

Which method used to attack ground cover fires is generally used against fires that are very hot, very big, and very fast?

Chemistry

1 answer:

AURORKA [14]3 years ago

6 0

Answer:

Indirect attack (ground cover)

Explanation:

Indirect attack (ground cover) is a method of controlling a groundcover fire whereby the control line is erected or situated at a remote from the main fire edge, and the fuel between the two points was burned.

The indirect attack is set up at some distance

from the raging fire. The indirect attack method is normally used to put out

fires that are too fast, too big or too hot for a direct attack method to work.

adjustments can be made when required

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The answer is copper

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3 years ago

Select the ion. a) NO2 b)H2SO4 c) Al+3 ...?

Gemiola [76]

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4 years ago

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What main type of forces must be overcome between br2 when liquid br2 dissolves into ethanol?

Snezhnost [94]

Dipole-induced dipole forces.

In contrast to C2H5OH, which is a very polar molecule, bromine is non-polar and has zero dipole moment. Charges are separated within polar molecules.

When a nonpolar Br2 molecule interacts with a polar C2H5OH molecule, one half of the bromine molecule acquires a charge and the other half acquires an opposing charge. A dipole is created when two adjacent bromine molecules have different charges. Bromine molecules must thus overcome the intermolecular forces—also known as dipole-induced dipole forces—that form in order to dissolve in ethanol.

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2 years ago

What is the molar mass of a gas with a density of 3.50 g/L at a

Kruka [31]

Answer:

104 g/mol

Explanation:

Use the ideal gas equation:

$pV=nRT$

Where:

p is pressure: 0.950atm
V is volume: unknown
n is number of moles: unknown
R is the universal constat of gases: 0.08206 atm.liter/ (K.mol)
T is the absolute temperature: 345K

Use the molar mass of the gas to include the density in the formula:

molar mass = mass in grams / number of moles

⇒ mass in grams = number of moles × molar mass

density = mass in grams / volume

⇒ density = number of moles × molar mass / volume

density = (n/V) × molar mass

⇒ n/V = density / molar mass

Clear n/V from the gas ideal equation and subsittute with density/molar mass:

n/V = p/(RT)

density / molar mass = n/V

density/molar mass = p/(RT)

molar mass = density × RT / p

Now you can subsitute the data:

molar mass = (3.50g/liter) × 0.08206 atm.liter/(K.mol) × 345K / 0.950 atm

molar mass = 104.3 g/mol

Round to the nearest whole number: 104g/mol ← answer

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Yuki888 [10]

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