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____ [38]
3 years ago
13

Please help asap!! it would mean a lot!! Thanks!!

Physics
1 answer:
Aleksandr-060686 [28]3 years ago
6 0
B. Frictional force is your answer :)
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At a pressure of one billionth (10–9) of atmospheric pressure, there are about 2.7 × 1010 molecules in one cubic centimeter of a
Sergeeva-Olga [200]

Answer:

Required answer =  2.7 x 10^16 MOLECULES

Explanation:

We know that

1 m = 100 cm

so 1 m^3 = (100 cm)^3 = 1000000 cm^3 = 1 x 10^6 cm3

as per question, 2.7*10^{10} molecules in 1 cm^3

so number of molecules in 1 m^3

Number of molecules = ( 2.7 x 10^10 molecules /1 cm^3 ) x ( 1 x 10^6 cm3 / 1 m3)

Number of molecules = 2.7 x 10^10 x 1 x 10^6 = 2.7 x 10^16 per m3

Required answer =  2.7 x 10^16 MOLECULES

3 0
3 years ago
Why do land animals including meat eaters depend on soil
dexar [7]
They depend on it because this helps them maintain nutirance and survive and reproduce more.
4 0
4 years ago
Seasons are caused by differences in daylight, temperature, and weather patterns due to :
Neko [114]

... the angular tilt of the Earth's position on its axis relative to the sun


4 0
4 years ago
What information do you think the temperatures of stars give us?
Paul [167]

Explanation:

One way of classifying stars is by their temperature .

or

Science strives to be able to describe how stars and planets form and evolve. This requires theories to describe the processes which include:

Star and planet formation

Star and planet composition

Stellar and solar system evolution

The nuclear processes happening inside stars

The scientific method means that all theories are put to the test. By measuring or calculating the temperature, age and composition of other planets and stars the theories can be tested. If observed values of these parameters are not predicted by theories, then the theories are wrong and need to be revised or replaced.

6 0
3 years ago
Read 2 more answers
Suppose the value of one division of vernier scale is 0.5mm and the value of one main scale
gregori [183]

Answer:

-0.01 mm

Explanation:

We are given that

The value of one division of vernier scale =0.5 mm

The value of one main scale division=0.49 mm

We have to find the value of least count of the instrument in mm.

We know that

Leas count of vernier caliper=1 main scale division-1 vernier scale division

Least count of vernier caliper=0.49-0.50=-0.01 mm

Hence, the least count of the instrument=-0.01 mm

Answer: -0.01 mm

8 0
4 years ago
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