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yulyashka [42]
4 years ago
15

Which is measured by the power of a machine?

Physics
2 answers:
zlopas [31]4 years ago
6 0

Answer: The correct answer is "the rate of doing work".

Explanation:

The expression for the power is as follows;

P=\frac{W}{t}

Here, P is the power, W is the work done and t is the time taken.

The unit of power is joule per second. The SI unit of power is watt. One watt is defined as one joule of amount of work is done in one second.

The power is defined as the rate of doing work. The power is directly proportional to the work done.

To increase power, increase the amount of work done in a given time or to increase power, do work in less time.

Therefore, the rate of doing work is measured by the power of a machine.

Anton [14]4 years ago
3 0

the word done by the machine

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What did ancient Greeks believe was at the center of the Universe? *
Natali [406]

The Greeks thought that the sun was the center of the Univesre for plantets like earth to observe it !!!

5 0
4 years ago
How much time does it take for a car traveling at 65 miles/hour to travel 300 miles
galina1969 [7]

Time taken by the car to travel 300 miles is 4.615 hours.

<h3>What is speed?</h3>

The speed of any moving object is the ratio of the distance traveled and the time taken to cover that distance.

Given is the distance d = 300 miles and the speed s = 65 miles/hour, then the time taken t will be

s=d/t

65 = 300/t

t= 4.615 hours

Thus, time taken by the car to travel 300 miles is 4.615 hours.

Learn more about speed.

brainly.com/question/7359669

#SPJ4

5 0
2 years ago
Which has a greater momentum: a ship weighing kg that is tied to a dock or a raindrop weighing kg that is falling from a cloud?
Illusion [34]

Answer: A raindrop

Explanation:

It would be a raindrop depending on if the ship is moving or not. If the ship is not moving, then the raindrop would have more momentum. But, if the ship were moving, then it would have more momentum. Because momentum equals mass times velocity.

8 0
3 years ago
What are the factor that affect the efficiency of a pulley​
alukav5142 [94]

Answer:

Tension in the chains - In a chain drive, technically, you have a closed-chain (which has no end) going around 2 pulley or gears; looking closely you have 2 parallel chains going in opposite direction. If kept in horizontal direction, the one below the other is the slack side and the other the tight side. The tension on the upper or tight side is more than the slack side. So you need to keep in mind to keep your chain drive tight so that there is no loss or rotation or lags.

Sizes of the pulley/gear - The chain will be warped around a pair of pulley or gear. The sizes of these pulley/gear will also determine the efficiency of the chain drive (consider one big and one small)

Number of pulley/gear - If the number of pulley/gear is more and chain wrapped on it with little complexity will result in decrease in efficiency because of extra tension.

Length of the chain drive - You cannot have much too long chain drive. It will make your slack side more heavy because the end are further away. You have to apply more power and possibilities of lag increases decreasing efficiency. In an ideal situation, this won't happen, but this world isn't ideal.

Friction between chains & pulley/gear - If you have studied gears (involving its teeth), you will come to know that there is friction offered on the two meeting surfaces.

Angle of contact - This would have been explained better with a diagram. Although, if you are familiar with the terms you won't have difficulty understanding. Angle of contact is the angle the chain forms with the pulley/gear at the point of contact with the center of the pulley. The angle of contact should not be too small, or else the things will be slippery.

Explanation:

8 0
4 years ago
A circus tightrope walker weighing 800 N is standing in the middle of a 15 meter long cable stretched between two posts. The cab
Lorico [155]

Answer:

T = 10010 N

Explanation:

To solve this problem we must use the translational equilibrium relation, let's set a reference frame

X axis

       Fₓ-Fₓ = 0

       Fₓ = Fₓ

whereby the horizontal components of the tension in the cable cancel

Y Axis  

        F_{y} + F_{y} - W =0

        2F_{y} = W

let's use trigonometry to find the angles

        tan θ = y / x

        θ = tan⁻¹ (0.30 / 0.50 L)

        θ = tan⁻¹ (0.30 / 0.50 15)

        θ = 2.29º

the components of stress are

         F_{y} = T sin θ

we substitute

       2 T sin θ = W

       T = W / 2sin θ

        T = \frac{ 800}{ 2sin 2.29}

        T = 10010 N

4 0
3 years ago
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