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4 years ago

In what ways do renewable resources differ from nonrenewable resources? Select three options.

Physics

2 answers:

Degger [83]4 years ago

8 0

Answer:

A, D, and E

Explanation:

Annette [7]4 years ago

4 0

A: Renewable resources make cleaner energy.

D: It often costs more to produce energy from renewable resources.

E: More local suppliers can provide energy from renewable resources to customers

Explanation:

Renewable sources of energy are cleaner and more accessible source of energy. They are easily replenished.

With current usage metrics, they can satisfactorily meet the energy demand of the world without affecting their supply.

Renewable energy include biomass, wind energy, wave energy, solar energy e.t.c
These energy sources are easily replenished.
To produce energy from renewable sources, it usually costs more.
Most equipment and devices that produces energy from renewable sources are highly pricey.
Renewable energy is the future of energy production.
Most smart cities around the world have solely relied on harnessing this source of energy.
They no carbon emission to the environment and would not lead to climate change.

learn more:

Non - renewable source of energy brainly.com/question/3386515

#learnwithBrainly

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the law of reflection states that if the angle of incidence is 77 degrees the angle of reflection is

zzz [600]

Answer: 77 degrees

Explanation:

According to the Law of Reflection, when a ray of light strikes a surface, the angle of this ray (incident ray) with respect to the normal of the surface is equal to the angle that forms the reflected ray with the same normal of the surface.

In other words:

Both the incident ray and the reflected ray and the normal to the surface are in the same plane, in addition, the angle of the incident ray is equal to the angle of the reflected ray.

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8 0

4 years ago

A solid sphere of diameter D = 26 cm has a charge of Q = 4 nano-coulombs uniformly distributed on it. Calculate the magnitude of

kozerog [31]

Answer:

E = 4.83 N/ C

Explanation:

If we have a uniform charge sphere we can use the following formulas to calculate the Electric field due to the charge of the sphere:

$E= \frac{k*Q}{r^{2} }$ : Formula (1) To calculate the electric field in the region outside the sphere r ≥ a

Where:

K: coulomb constant (N*m²/C²)

a: sphere radius (m)

Q: Total sphere charge (C)

r : Distance from the center of the sphere to the region where the electric field is calculated (m)

Equivalences

1nC=10⁻⁹C

1cm= 10⁻²m

Data

k= 9*10⁹ N*m²/C²

Q=4nC=4 *10⁻⁹C

D = 26 cm = 26*10⁻²m = 0.26m

a = D/2 = 0.13m

r= R+a = 2.6 m+ 0.13m = 2.73m

Problem development

Magnitude of the electric field at r = 2.73m from the center of the sphere

r>a , We apply the Formula (1) :

$E= \frac{k*Q}{r^{2} }$

$E= \frac{9*10^{9}*4*10^{-9} }{2.73^{2} }$

E= 4.83 N/ C

3 0

3 years ago