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Over [174]
3 years ago
5

If you go to columbiana middle put your real name

Physics
2 answers:
ololo11 [35]3 years ago
5 0

Answer:

its in my user

Explanation:

olga_2 [115]3 years ago
3 0

Answer:

Nooooooooooooooooooo u

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How much work is done? A Net Force of 9.0 N acts through a distance of 3.0 m in a time of 3.0 s. The answers are 3.0 J, 9.0 J, 2
Vadim26 [7]
If the force and the motion are along the same direction (like it is here) then work is force*distance.  The time doesn't come into play until you want the power used.  So here
W=9.0*3.0=27J
5 0
3 years ago
A high-jump athlete leaves the ground, lifting her center of mass 1.8 m and crossing the bar with a horizontal velocity of 1.4 m
Romashka [77]

Answer:

The minimum speed when she leave the ground is 6.10 m/s.

Explanation:

Given that,

Horizontal velocity = 1.4 m/s

Height = 1.8 m

We need to calculate the minimum speed must she leave the ground

Using conservation of energy

K.E+P.E=P.E+K.E

\dfrac{1}{2}mv_{1}^2+0=mgh+\dfrac{1}{2}mv_{2}^2

\dfrac{v_{1}^2}{2}=gh+\dfrac{v_{2}^2}{2}

Put the value into the formula

\dfrac{v_{1}^2}{2}=9.8\times1.8+\dfrac{(1.4)^2}{2}

\dfrac{v_{1}^2}{2}=18.62

v_{1}=\sqrt{2\times18.62}

v_{1}=6.10\ m/s

Hence, The minimum speed when she leave the ground is 6.10 m/s.

6 0
3 years ago
Acceleration is measured in_________<br><br><br> m<br><br><br> g<br><br><br> m/s<br><br><br> m/s2
Nana76 [90]
Acceleration is measured in m/s².

Answer: m/s²
4 0
3 years ago
4. Premature wrinkling due to overexposure to the Sun, what am I?​
Irina-Kira [14]

Premature Aging

Mark as brainlist

5 0
2 years ago
The graph shows the range of frequencies commonly heard by some animals.
Vsevolod [243]

Concept:

Frequency- It is defined as the number of oscillations occur in one second.

Its SI unit is Hertz (Hz)

Given: Produced sound vibrations is 18,500 cycles in 0.75 seconds

∵ In 0.75 second, produced sound has oscillations = 18,500 cycles

∴ In 1.0 second, produced sound has oscillations = (18,500 ÷ 0.75) Hz

The frequency of the sound will be ≈ 24,667 Hz

From the study of the given graph, only the animals (c) Cats, (b) Moths and (a) Bats can hear the produced sound because their upper audible frequency range is greater than 24,667 Hz.

3 0
3 years ago
Read 2 more answers
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