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The Energy flux from Star B is 16 times of the energy flux from Star A.
We have Two stars - A and B with 4900 k and 9900 k surface temperatures.
We have to determine how many times larger is the energy flux from Star B compared to the energy flux from Star A.
<h3>State Stephen's Law?</h3>Stephens law states that if E is the energy radiated away from the star in the form of electromagnetic radiation, T is the surface temperature of the star, and σ is a constant known as the Stephan-Boltzmann constant then-
Now -
Energy emitted per unit surface area of Star is called Energy flux. Let us denote it by E. Then -
Now -
For Star A →
= 4900 K
For Star B →
= 9900 K
Therefore -
2.02 = 2 (Approx.)
Now -
Assume that the energy flux of Star A is E(A) and that of Star B is E(B). Then -
E(B) = E(A) x
E(B) = E(A) x
E(B) = 16 E(A)
Hence, the Energy flux from Star B is 16 times of the energy flux from Star A.
To learn more about Stars, visit the link below-
#SPJ4
Answer:
11.2Watts
Explanation:
Given parameters:
Energy produced by the engine = 670J
Time taken = 1min = 60s
Unknown:
Number of watts it can output = ?
Solution:
This problem entails finding the power of the engine.
Power is the rate at which work is being done.
So;
Power =
Power = = 11.2Watts