Is it just me or can anyone else not see a graph? (Because I can’t)
Answer:
5 I think will be none of the above and 6 could be all of the above
I assume that the ball is stationary (v=0) at point B, so its total energy is just potential energy, and it is equal to 7.35 J.
At point A, all this energy has converted into kinetic energy, which is:
![K= \frac{1}{2}mv^2](https://tex.z-dn.net/?f=K%3D%20%5Cfrac%7B1%7D%7B2%7Dmv%5E2%20)
And since K=7.35 J, we can find the velocity, v:
Answer:
The value is ![C = 30729\ c](https://tex.z-dn.net/?f=C%20%3D%2030729%5C%20%20c)
Explanation:
From the question we are told that
The power rating of the stove is ![P = 4.4 KW = 4.4 *10^{3} \ W](https://tex.z-dn.net/?f=P%20%3D%204.4%20KW%20%20%3D%204.4%20%2A10%5E%7B3%7D%20%5C%20%20W)
The duration of its use everyday is
The rating of the light bulbs is ![P_2' = 150 W](https://tex.z-dn.net/?f=P_2%27%20%20%3D%20150%20W)
The number is ![n = 7](https://tex.z-dn.net/?f=n%20%3D%207)
The power rating of the total bulb is ![P_2 = 7 * 150 = 1050 \ W](https://tex.z-dn.net/?f=P_2%20%3D%207%20%2A%20150%20%3D%201050%20%5C%20%20W)
The duration of its use everyday is ![t_2 = 7 hours](https://tex.z-dn.net/?f=t_2%20%20%3D%207%20hours)
The power rating of miscellaneous appliance ![P_3 = 1.8 \ KW = 1.8 *10^{3} \ W](https://tex.z-dn.net/?f=P_3%20%3D%201.8%20%5C%20KW%20%3D%201.8%20%2A10%5E%7B3%7D%20%5C%20%20W)
The duration of its use everyday is ![t_3 = 1 hour](https://tex.z-dn.net/?f=t_3%20%3D%201%20hour)
The power rating of hot water ![P = 4 KW = 4 *10^{3} \ W](https://tex.z-dn.net/?f=P%20%3D%204%20KW%20%20%3D%204%20%2A10%5E%7B3%7D%20%5C%20%20W)
The duration of its use everyday is ![t_4 = 120 \ minutes = 2 hours](https://tex.z-dn.net/?f=t_4%20%3D%20120%20%5C%20minutes%20%20%3D%202%20hours)
Generally the total electrical energy used in 1 month is mathematically represented as
![E = P_1 * t_1 * 30 + P_2 * t_2 * 30 + P_3 * t_3 * 30+ P_4 * t_4 * 30](https://tex.z-dn.net/?f=E%20%3D%20P_1%20%2A%20t_1%20%2A%2030%20%2B%20P_2%20%2A%20t_2%20%2A%2030%20%2B%20P_3%20%2A%20t_3%20%2A%2030%2B%20P_4%20%2A%20t_4%20%2A%2030)
=> ![E = 4.4*10^{3} * 1.167 * 30 + 1050 * 7 * 30 + 1.8 *1 * 30+ 4*10^{3} * 2 * 30](https://tex.z-dn.net/?f=E%20%3D%204.4%2A10%5E%7B3%7D%20%2A%201.167%20%20%2A%2030%20%2B%201050%20%2A%207%20%2A%2030%20%2B%201.8%20%2A1%20%2A%2030%2B%204%2A10%5E%7B3%7D%20%2A%202%20%2A%2030)
=> ![E = 614598 \ W \cdot h](https://tex.z-dn.net/?f=E%20%3D%20614598%20%20%5C%20W%20%5Ccdot%20h)
=> ![E = 614.6 \ K W \cdot h](https://tex.z-dn.net/?f=E%20%3D%20614.6%20%20%5C%20%20K%20W%20%5Ccdot%20h)
Generally the monthly electricity bill is mathematically represented as
![C = 614.6 * 50](https://tex.z-dn.net/?f=C%20%3D%20614.6%20%2A%2050)
=> ![C = 30729\ c](https://tex.z-dn.net/?f=C%20%3D%2030729%5C%20%20c)
Answer:
O The particles of the medium move more slowly and there are fewer chances to transfer energy.
Explanation:
Various media are made up of particles. These particles are in constant motion according to the kinetic theory of matter. Recall that temperature has been defined as the average kinetic energy of the particles in a medium. Hence, for any given medium, the velocity of particle motion increases or decreases linearly with temperature.
The speed of particles in any medium increases or decreases as the temperature of the medium increases or decreases as emphasised above. Hence, at low temperature, the velocity of waves set up by the motion of particles in a medium decreases and transfer the wave energy to neighbouring particles occurs more slowly than at high temperatures.