All categories

1 year ago

What type of energy does a pv cell create ?

Physics

2 answers:

swat321 year ago

7 0

I’m not exactly sure but I hope some one can answer it

Alex_Xolod [135]1 year ago

6 0

Answer: Solar Photovoltaic (PV) cells generate electricity by absorbing sunlight and using that light energy to create an electrical current. There are many PV cells within a single solar panel, and the current created by all of the cells together adds up to enough electricity to help power your school, home and businesses.

--Cited from Solar Schools

You might be interested in

12. A rocket, initially at rest on the ground, accelerates vertically. It accelerates uniformly until it

vodomira [7]

Answer:

We kindly invite you to read carefully the explanation and check the image attached below.

Explanation:

According to this problem, the rocket is accelerated uniformly due to thrust during 30 seconds and after that is decelerated due to gravity. The velocity as function of initial velocity, acceleration and time is:

$v_{f} = v_{o}+a\cdot (t-t_{o})$ (1)

Where:

$v_{o}$ - Initial velocity, measured in meters per second.

$v_{f}$ - Final velocity, measured in meters per second.

$a$ - Acceleration, measured in meters per square second.

$t_{o}$ - Initial time, measured in seconds.

$t$ - Final time, measured in seconds.

Now we obtain the kinematic equations for thrust and free fall stages:

Thrust ( $v_{o} = 0\,\frac{m}{s}$ , $a = 30\,\frac{m}{s^{2}}$ , $t_{o} = 0\,s$ , $0\,s\le t< 30\,s$ )

$v = 30\cdot t$ (2)

Free fall ( $v_{o} = 900\,\frac{m}{s}$ , $a = -9.807\,\frac{m}{s}$ , $t_{o} = 30\,s$ , $30\,s \le t \le 120\,s$ )

$v = 900-9.81\cdot (t-30)$ (3)

Now we created the graph speed-time, which can be seen below.

5 0

2 years ago

A ball is projected with an initial velocity of 40 meter per second and reached maximum height of 160 meters calculate tge angle

Andru [333]

There's a problem with the question as given. Even with a maximum projection angle of θ = 90°, the initial velocity is not large enough to get the ball up in the air 160 m. With angle 90°, the ball's height y at time t would be

y = (40 m/s) t - 1/2 g t ²

Set y = 160 m, and you'll find that there is no (real) solution for t, so the ball never attains the given maximum height.

From another perspective: recall that

v ² - v₀² = 2a ∆y

where

• v₀ = initial velocity

• v = final velocity

• a = acceleration

• ∆y = displacement

At its maximum height, the ball has zero vertical velocity, and ∆y = maximum height = 160 m. The ball is in free fall once it's launched, so a = -g.

So we have

0² - (40 m/s)² = -2g (160 m)

but this reduces to

(40 m/s)² = 2 (9.8 m/s²) (160 m)

1600 m²/s² ≠ 3136 m²/s²

7 0

2 years ago

An engineering team has come to the stage in the engineering design

SIZIF [17.4K]

Answer: D

Explanation: read the answers above and compare to your test

6 0

2 years ago

A surveyor is using a magnetic compass 6.4 m below a power line in which there is a steady current of 120 A. (a) What is the mag

Mademuasel [1]

Answer:

Explanation:

Magnetic field due to a long current carrying conductor

μ₀ / 4π x 2i / r ( i = current , r = distance of point from wire )

= 10⁻⁷ x 2 x 120 / 6.4 ( i = 120 A , r = 6.4m )

= 37.5 x 10⁻⁷ T .

= 3. 75 X 10⁻⁶ T .

= 3.75 µT.

b )

The direction of this field will be horizontal hence it will affect magnetic needle.

6 0

3 years ago

Read 2 more answers

Owen throws a baseball straight upward. We can ignore air resistance.

dusya [7]

Answer:

The acceleration of the ball is constant and equal to -9.81 m/s² (acting downwards)

The velocity of the ball reduces at a constant rate with time on its way up

Explanation:

The motion of the ball upwards is described by the following equation;

v = u - g × t

v² = u² - 2 × g × s

Where;

v = The final velocity of the ball

u = The initial velocity of the ball

g = The acceleration due to gravity = Constant

s = The height of the bass after a given time, t

t = The time in which the ball is rising

Therefore, the acceleration of the ball = The acceleration due to gravity (Constant) = -9.81 m/s²↓

From v = u - g × t = u - 9.81 × t , the velocity of the ball reduces at a constant rate with time on its way up.

7 0

2 years ago