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BigorU [14]
3 years ago
15

what would have happened if there had been satellites during the time of the 1900 galveston hurricane?

Physics
1 answer:
vovangra [49]3 years ago
8 0
The satellites most likely would’ve helped prevent a lot of deaths, and be able to use the information to warn the people in the area before it hit.
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A potter spins his wheel at 0.98 rev/s. The wheel has a mass of 4.2 kg and a radius of 0.35 m. He drops a chunk of clay of 2.9 k
Bad White [126]

Answer:

v_{f,w} = 1.791\,\frac{m}{s}, v_{f,c} = 0.972\,\frac{m}{s}

Explanation:

The situation can be modelled by applying the Principle of Angular Momentum Conservation:

I_{w} \cdot \omega_{o} = (I_{w} + I_{c})\cdot \omega_{f}

The final angular speed is:

\omega_{f} = \frac{I_{w}}{I_{w}+I_{c}}\cdot \omega_{o}

\omega_{f} = \left(\frac{\frac{1}{2}\cdot (4.2\,kg)\cdot (0.35\,m)^{2} }{\frac{1}{2}\cdot (4.2\,kg)\cdot (0.35\,m)^{2} + \frac{1}{2}\cdot (2.9\,kg)\cdot (0.19\,m)^{2}}\right)\cdot (0.98\,\frac{rev}{s} )\cdot \left(\frac{2\pi\,rad}{1\,rev}  \right)

\omega_{f} \approx 5.116\,\frac{rad}{s}

The tangential velocities of the wheel and the clay are, respectively:

v_{f, w} = (0.35\,m)\cdot (5.116\,\frac{rad}{s} )

v_{f,w} = 1.791\,\frac{m}{s}

v_{f, c} = (0.19\,m) \cdot (5.116\,\frac{rad}{s} )

v_{f,c} = 0.972\,\frac{m}{s}

5 0
3 years ago
Calculate the centripetal force (in N) on the end of a 44 m (radius) wind turbine blade that is rotating at 0.7 rev/s. Assume th
Andrews [41]
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4 0
3 years ago
Read 2 more answers
A phone cord is 2.28 m long. The cord has a mass of 0.2 kg. A transverse wave pulse is produced by plucking one end of the taut
Debora [2.8K]

The characteristics of the speed of the traveling waves allows to find the result for the tension in the string is:  

         T = 10 N

The speed of a wave on a string is given by the relationship.

      v =\sqrt{\frac{T}{\mu } }

Where   v es the velocty, t is the tension ang μ is the lineal density.

They indicate that the length of the string is L = 2.28 m and the pulse makes 4 trips in a time of t = 0.849 s, since the speed of the pulse in the string is constant, we can use the uniform motion ratio, where the distance traveled e 4 L

           v = \frac{d}{t}  

           v = \frac{4 L}{t}  

           v = \frac{4 \ 2.28 }{0.849}  

            v = 10.7  m / s

Let's find the linear density of the string, which is the length of the mass divided by its mass.

            μ = \frac{m}{L}  

            \mu = \frac{0.2}{2.28}  

            μ = 8.77 10⁻² kg / m

The tension is:

        T = v² μ

Let's calculate

        T = 10.7²  8.77 10⁻²

        T = 1 0 N

In conclusion using the characteristics of the velocity of the traveling waves we can find the result for the tension in the string is:

         T = 10 N

Learn more here:  brainly.com/question/12545155

7 0
3 years ago
If the magnitude of vector A⃗ is less than the magnitude of vectorB⃗ , then the x component of A⃗ is less than the x component o
Mama L [17]
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5 0
3 years ago
A car weighing 9800 N travels at 30 m/s. What braking force brings it to rest in 100m? In 10 m?
Svetach [21]

As per kinematics equation we know that

final speed of the car = 0 m/s

initial speed is given as 30 m/s

distance moved = 100 m

now we have

v_f^2 - v_i^2 = 2 a d

0 - 30^2 = 2(a)(100)

a = - 4.5 m/s^2

now braking force is given as

F = ma

now for mass we know that the weight of car is

W = mg = 9800 N

so mass of car is

m = 1000 kg

now we have

F = 1000(4.5) = 4500 N

Part b)

Again we have

final speed of the car = 0 m/s

initial speed is given as 30 m/s

distance moved = 10 m

now we have

v_f^2 - v_i^2 = 2 a d

0 - 30^2 = 2(a)(10)

a = - 45 m/s^2

now braking force is given as

F = ma

mass of car is

m = 1000 kg

now we have

F = 1000(45) = 45000 N

4 0
3 years ago
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