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nevsk [136]
3 years ago
5

1. Find the Least Common Multiple of these two monomials: See picture

Mathematics
1 answer:
gtnhenbr [62]3 years ago
3 0

Answer:

<em>The last choice is correct</em>

<em />LCM=120a^4b^7c^5<em />

Step-by-step explanation:

<u>Least Common Multiple (LCM)</u>

To find the LCM we can follow this procedure:

List the prime factors of each monomial.

Multiply each factor the greatest number of times it occurs in either factor.

We have two monomials:

12a^4b^2c^5

40a^3b^7c^1

The prime factors of the first monomial are:

2^2,3,a^4,b^2,c^5

The prime factors of the second monomial are:

2^3,5,a^3b^7c^1

LCM = Multiply 2^3*3*5*a^4*b^7*c^5

These are all the factors the greatest number of times they occur.

Operating:

LCM=8*15*a^4*b^7*c^5

\boxed{LCM=120a^4b^7c^5}

The last choice is correct

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Step-by-step explanation:

\frac{ {13}^{6}  \div  {13}^{8}  \times  {13}^{ - 4} }{ {13}^{ - 2} }

You need to remember the properties of exponents: multiplication adds the exponents, division subtracts the exponents.

If you multiply two powers with the same base, the result will be the base to the sum of the powers.

If you divide two powers with the same base, the result will be the base to the difference of the powers.

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{13}^{ - 4}

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7 0
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Answer : x= -7/3 or in mixed number : -2 1/3

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Step-by-step explanation:

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