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nevsk [136]
3 years ago
5

1. Find the Least Common Multiple of these two monomials: See picture

Mathematics
1 answer:
gtnhenbr [62]3 years ago
3 0

Answer:

<em>The last choice is correct</em>

<em />LCM=120a^4b^7c^5<em />

Step-by-step explanation:

<u>Least Common Multiple (LCM)</u>

To find the LCM we can follow this procedure:

List the prime factors of each monomial.

Multiply each factor the greatest number of times it occurs in either factor.

We have two monomials:

12a^4b^2c^5

40a^3b^7c^1

The prime factors of the first monomial are:

2^2,3,a^4,b^2,c^5

The prime factors of the second monomial are:

2^3,5,a^3b^7c^1

LCM = Multiply 2^3*3*5*a^4*b^7*c^5

These are all the factors the greatest number of times they occur.

Operating:

LCM=8*15*a^4*b^7*c^5

\boxed{LCM=120a^4b^7c^5}

The last choice is correct

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4x+x=180  combine like terms on left side

5x=180  divide both sides by 5

x=36°
3 0
3 years ago
E: f= 3:7<br> f:g= 2:3<br> Work out e:9
Ksenya-84 [330]

Answer:

e f f g

3 7 2 3

6 14 14 21

e;g=6:21

e : g=2 : 7

Step-by-step explanation:

8 0
2 years ago
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andreev551 [17]

Answer:

p_v =P(t_{74}    

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Step-by-step explanation:

Data given and notation    

\bar X=18.81 represent the average lateral recumbency for the sample    

s=8.4 represent the sample standard deviation    

n=75 sample size    

\mu_o =20 represent the value that we want to test    

\alpha represent the significance level for the hypothesis test.    

t would represent the statistic (variable of interest)    

p_v represent the p value for the test (variable of interest)    

State the null and alternative hypotheses.    

We need to apply a left tailed  test.  

What are H0 and Ha for this study?    

Null hypothesis:  \mu \geq 20  

Alternative hypothesis :\mu < 20  

Compute the test statistic  

The statistic for this case is given by:  

t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}} (1)    

t-test: "Is used to compare group means. Is one of the most common tests and is used to determine if the mean is (higher, less or not equal) to an specified value".    

Calculate the statistic    

We can replace in formula (1) the info given like this:    

t=\frac{18.81-20}{\frac{8.4}{\sqrt{75}}}=-1.227

The degrees of freedom are given by:

df=n-1=75-1=74    

Give the appropriate conclusion for the test  

Since is a one side left tailed test the p value would be:    

p_v =P(t_{74}    

Conclusion    

If we compare the p value and a significance level for example \alpha=0.1 we see that p_v>\alpha so we can conclude that we have enough evidence to FAIL to reject the null hypothesis, so we can conclude that the true mean it's not significantly less than 20 min.

3 0
3 years ago
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Answer:

9

Step-by-step explanation:

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Similarly, for any integer, n, that is > 1 ; related by the expression ;

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Therefore,

If n = 3 ; a = 729

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To obtain the value of p ; take the cube of both sides

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6 0
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Answer:

\boxed{\sf (a + 3)(a + 1)}

Step-by-step explanation:

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7 0
2 years ago
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