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2 years ago

Which situation could not represent a proportional relationship?

Mathematics

2 answers:

Natasha_Volkova [10]2 years ago

7 0

Megan bought a fridge for $499 plus $100 delivery fee is not a proportional relationship.

sesenic [268]2 years ago

7 0

The 3 one does not represent a proportional representation

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Solve for x: - 4 + x > 5

Rufina [12.5K]

Answer:

x>9 this is the correct answer

6 0

3 years ago

Arturo, Pedro y Jorge son hermanos y duermen en la misma habitación. Su padre compró pintura para que entre los tres pinten su c

mr Goodwill [35]

Answer:

Tanto Pedro como Jorge deberán pintar 1/4 de la habitación cada uno.

Step-by-step explanation:

Dado que el cuarto entero es igual a 1, y que Arturo por ser el mayor de los hermanos tiene que pintar 1/2 de él, la parte que falta pintar es igual a 1/2 restante.

De ese 1/2, los hermanos menores, Pedro y Jorge, deben pintar dicha fracción en partes iguales. Por lo tanto, dado que (1/2) / 2 es igual a 1/4, la fracción que tanto Pedro como Jorge deberán pintar es de 1/4 de la habitación.

4 0

2 years ago

Read 2 more answers

What is the side length, in inches, of the pets

tatiyna

Candy draws a square design with a side length of x inches for the window at the pet shop. She takes the design to the printer and asks for a sign that has an area of 16x2 – 40x + 25 square inches. What is the side length, in inches, of the pet shop sign?

Answer:

the length of the sign is $4x-5$ inches

Step-by-step explanation:

Given

Area of the square of design = $16x^{2} -40x+25$

First we find the roots of equation $16x^{2} -40x+25=0$

The roots of the quadratic equation $ax^{2} +bx^{2} +c=0$ are given by

$x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}$

where $a=16, b=-40, c=25$

$x=\frac{40\pm\sqrt{(-40)^2-4\times 16\times 25}}{2\times 16}$

$x=\frac{40\pm\sqrt{1600-1600}}{32}$

$x=\frac{40\pm\sqrt{0}}{32}$

$x=\frac{40}{32}$

$x=\frac{5}{4}$

$4x=5\\4x-5=0$

That is, the factors of the polynomial $16x^{2} -40x+25$ are $4x-5$ and $4x-5$ .

So, Area of the square design = $16x^{2} -40x+25$ = $(4x-5)^{2}$

Area of a square = Length^2

Thus, the length of the sign is $4x-5$ inches

7 0

2 years ago

Find the perimeter of the pentagon MNPQR with vertices M(2, 4), N(5, 8), P(8, 4), Q(8, 1), and R(2, 1)

Gekata [30.6K]

Answer:

The pentagon MNPQR has a perimeter of 22 units.

Step-by-step explanation:

Geometrically speaking, the perimeter of the pentagon is the sum of the lengths of each side, that is:

$p = MN + NP + PQ + QR + RM$ (1)

$p = \sqrt{\overrightarrow{MN}\,\bullet \, \overrightarrow{MN}} + \sqrt{\overrightarrow{NP}\,\bullet \, \overrightarrow{NP}} + \sqrt{\overrightarrow{PQ}\,\bullet \, \overrightarrow{PQ}} + \sqrt{\overrightarrow{QR}\,\bullet \, \overrightarrow{QR}} + \sqrt{\overrightarrow{RM}\,\bullet \, \overrightarrow{RM}}$ (1b)

If we know that $M(x,y) = (2,4)$ , $N(x,y) = (5,8)$ , $P(x,y) = (8,4)$ , $Q(x,y) = (8,1)$ and $R(x,y) = (2,1)$ , then the perimeter of the pentagon MNPQR is:

$p =\sqrt{(5-2)^{2}+(8-4)^{2}} + \sqrt{(8-5)^{2}+(4-8)^{2}}+\sqrt{(8-8)^{2}+(1-4)^{2}}+\sqrt{(2-8)^{2}+(1-1)^{2}}+\sqrt{(2-2)^{2}+(4-1)^{2}}$ $p = \sqrt{3^{2}+4^{2}} + \sqrt{3^{2}+(-4)^{2}}+\sqrt{0^{2}+(-3)^{2}}+\sqrt{(-6)^{2}+0^{2}}+\sqrt{0^{2}+3^{2}}$

$p = 22$

The pentagon MNPQR has a perimeter of 22 units.

4 0

2 years ago

Please help me with this probability question.

Vikki [24]

Answer:

1.6 please correct me if im wrong by commenting

Step-by-step explanation:

6 0

3 years ago