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rodikova [14]
3 years ago
13

11 - y = 3 + 6x I need to solve the literal equation for y, but I don’t get it

Mathematics
2 answers:
zaharov [31]3 years ago
8 0

Answer:

y=-6x+8

Step-by-step explanation:

A literal equation is an equation where variables represent known values. Literal equations allow use to represent things like distance, time, interest, and slope as variables in an equation. Using variables instead of words

                 11 - y =   3 + 6x

                -11 -y    = 3 -11 +6x

----------------------------------------------------

                 0-y  =   -8 +6x

Multiply everything by -1

             y= -6x=8

klio [65]3 years ago
7 0

Answer:  y = -6x + 8

Step-by-step explanation:

11 - y = 3 + 6x

<u>-11       -11</u>

<u>-y = -8 + 6x</u>

      -1

y = -6x + 8

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Combine like terms to create an equivalent expression<br> 3x²+5y²-x^2+2y^2-4
Alja [10]

Answer

3x²+5y²-x^2+2y^2-4

2x^2+7y^2-4

7 0
3 years ago
2 wholes and 3/12 + 3/? = 2 wholes and 5/8 .what is the missing number ?
Sladkaya [172]
Basically you know that the 2 wholes from both sides cancel out.

Set up the equation, 5/8 = 3/12 + 3/x

3/x =  5/8 - 3/12

Set them to have a common denominator, 3/x = 15/24 - 6/24

3/x = 9/24

Simplify 9/24 and you will get 3/8

3/x = 3/8

Obviously this means x = 8


6 0
3 years ago
The table of a linear function is partially completed below. What is the missing y-value to complete the table?
NeTakaya
The missing answer would be -2
4 0
3 years ago
Read 2 more answers
I really need help ASAP PLEASEEEE !!
STALIN [3.7K]
It would be 270,725. The last choice.
4 0
3 years ago
A piece of cardboard measures 10 ft by 10 ft. Four equal squares of size x are removed from the corners. After removing the squa
Gnesinka [82]

Answer:

The value of x would be \frac{5}{3}

Step-by-step explanation:

Given,

The dimension of the cardboard = 10 ft by 10 ft,

∵ After removing four equal squares of size x ( in ft ) from the corners,

The dimension of the resultant box would be,

Length = ( 10 - 2x ) ft,

Width = ( 10 - 2x ) ft,

Height = x ft,

The volume of box,

V=(10-2x)\times (10 - 2x)\times x=x(10-2x)^2 = x(100 - 40x + 4x^2)=100x - 40x^2 + 4x^3

Differentiating with respect to x,

V'=100 - 80x + 12x^2

Again differentiating with respect to x,

V''=-80 + 24x

For maxima or minima,

V'=0

\implies 100 - 80x + 12x^2 = 0

\implies 3x^2 - 20x + 25=0

By quadratic formula,

x=\frac{20\pm \sqrt{20^2-4\times 3\times 25}}{6}

x=\frac{20\pm \sqrt{400 - 300}}{6}

x=\frac{20\pm \sqrt{100}}{6}

x=\frac{20\pm 10}{6}

\implies x = \frac{10}{6}=\frac{5}{3}\text{ or } x = 5

For x = 5/3, V'' = negative,

While for x = 5, V'' = Positive,

Hence, the value of x would be 5/3 ft for maximising the volume.

8 0
4 years ago
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