Dimensions of walkway and pool= (23+3) x (32+3) => 26ft x 35 ft
Perimeter: 2(l+w)
= 2 (26ft + 35ft)
= 122 ft fence would be required to enclose the walkway and the pool.
Domain is the years from 2000 through 2020 inclusive
<span>at 2000, t = 2000-2009 = -9 </span>
<span>at 2020, t = 2020-2009 = 11 </span>
<span>Domain: -9 ≤ t ≤ 11 </span>
<span>P(t) = 80(0.98)t </span>
<span>Since population models are almost always exponential, I'll assume you meant the "t" to be an exponent and the model should be: </span>
<span>P(t) = 80•0.98^t = 80 → t = 0 </span>
<span>The population is 80 at t = 0. The year corresponding to t = 0 is 2009</span>
3(8-2x)
Distribute/Multiply 3 into 8 and -2x
3*8 - 3*2x
Final Answer: 24 - 6x
For the answer to this, we turn to the all-important Fundamental Theorem of Algebra<em /><em>, </em>which states that every degree-<em>n</em> polynomial has exactly <em>n </em>imaginary roots. It's important to keep in mind that this theorem doesn't tell you how to <em>find </em>these roots - it just tells you that they <em>exist</em>.
Answer:
Step-by-step explanation:
1) Area of garden = side * side
= 10* 10
= 100 Sq.m
2) Area of each flowerbed = 1*1 = 1 sqm
3) Area of 4 flowerbed = 1 * 4 = 4 sqm
Area of the remaining garden = Area of garden - area of 4 flower bed
= 100 - 4
= 96 sq.m
4) Length of the fence = 4 *side
= 4 * 10 = 40 m
5) Cost of planting in the remaining garden = 96 * 20
= ₹ 1920
