Answer:
m=1
Step-by-step explanation:
(8,18);(2,12)
(x1,y1)=(8,18)
(x2,y2)=(2,12)
Use the slope formula:
A) 1:4
B) 44
There are 11 grey slabs and 44 yellow slabs.
The property of a(b+(-b))=(b+(-b))a is called as Commutative Property of Multiplication.
The Commutative Property in mathematics is a rule that allows interchange the order of terms or factors without any change in the end result.
In multiplication, we can interchange the factors without affecting the end result of multiplication. For example, 2 x 3 = 3 x 2 = 6
In addition, we can interchange the terms without affecting the summation result. For example, 2+3 = 3+2 = 5
But Commutative Property does not apply to subtraction or division.
For example, 2-3 != 3-2
or, 2/3 != 3/2
Hence the answer to the question is Commutative Property of Multiplication.
To know more about "Commutative" click here
brainly.com/question/28747013
#SPJ1
Answer:
The order of the start of the proof seems fine; we're to choose the next steps I guess.
segment UV is parallel to segment WZ Given
Points S, Q, R, and T all lie on the same line. Given
m∠SQT = 180° Definition of a Straight Angle
m∠SQV + m∠VQT = m∠SQT Angle Addition Postulate
m∠SQV + m∠VQT = 180° Substitution Property of Equality
That's all valid up to here. It seems to me sort of the hard way to get to linear supplements but here we are.
ZRS is mentioned in the rest of the lines; let's find the one that comes first.
III m∠VQT + m∠ZRS = 180° Same-Side Interior Angles Theorem
Now we have two things equal to 180 degrees, so they're equal to each other.
II m∠SQV + m∠VQT = m∠VQT + m∠ZRS Substitution Property of Equality
Now comes
I m∠SQV + m∠VQT − m∠VQT = m∠VQT + m∠ZRS − m∠VQT
m∠SQV = m∠ZRS Subtraction Property of Equality
And we conclude,
∠SQV ≅ ∠ZRS Definition of Congruency
Answer:
C
Step-by-step explanation:
We have the equation:
![4x^2+5x=-10](https://tex.z-dn.net/?f=4x%5E2%2B5x%3D-10)
Add 10 to both sides to isolate the equation.
![4x^2+5x+10=0](https://tex.z-dn.net/?f=4x%5E2%2B5x%2B10%3D0)
This is not factorable*, so we can use the quadratic formula:
![\displaystyle x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}](https://tex.z-dn.net/?f=%5Cdisplaystyle%20x%3D%5Cfrac%7B-b%5Cpm%5Csqrt%7Bb%5E2-4ac%7D%7D%7B2a%7D)
In this case, <em>a</em> = 4, <em>b</em> = 5, and <em>c</em> = 10.
Substitute:
![\displaystyle x=\frac{-(5)\pm\sqrt{(5)^2-4(4)(10)}}{2(4)}](https://tex.z-dn.net/?f=%5Cdisplaystyle%20x%3D%5Cfrac%7B-%285%29%5Cpm%5Csqrt%7B%285%29%5E2-4%284%29%2810%29%7D%7D%7B2%284%29%7D)
Simplify:
![\displaystyle x=\frac{-5\pm\sqrt{-135}}{8}](https://tex.z-dn.net/?f=%5Cdisplaystyle%20x%3D%5Cfrac%7B-5%5Cpm%5Csqrt%7B-135%7D%7D%7B8%7D)
Since we cannot take the root of a negative, we have no real solutions.
Our answer is C.
*To factor something in the form of:
![ax^2+bx+c=0](https://tex.z-dn.net/?f=ax%5E2%2Bbx%2Bc%3D0)
We want two numbers <em>p</em> and <em>q</em> such that <em>pq</em> = <em>ac</em> and <em>p</em> + <em>q</em> = <em>b</em>.
Since <em>ac</em> = 4(10) = 40. We need to find two whole numbers that multiply to 40 and add to 5.
No such numbers exist, so the equation is not factorable.