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dybincka [34]
2 years ago
14

The area of a square floor on a scale drawing is 36 square centimeters, and the scale drawing is

Mathematics
1 answer:
goldfiish [28.3K]2 years ago
6 0

Area of a square = x² ( x is the length of a side)

Area = 36cm² = x² = 6²

length of one side of the square in the scale drawing = 6cm

since the diagram is scaled to 1cm : 3ft

the actual length = 6 × 3 ft = 18ft

the actual area = x² = 18² = 324 ft²

the ratio of the area in the drawing to the

actual area is

36 cm² : 324 ft²

to get the simplest ratio we divide both sides by 36 ( as 36 is the factor they both share in common)

the simplest ratio of the area in the drawing to the

actual area is

1 : 9

Hope you understood :)

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The number of standard deviations from the mean for a man 72 inches tall is
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3 years ago
Find the volume of the solid below.
Semenov [28]

Answer:

Volume = V=  346.43 cm ^3

Step-by-step explanation:

15.32 x 10 = 153.2cm Area of side

We find the height of the cylinder, to enable the radius/2 for the circle side x 2

it would be the same as triangle side 6 but the exact circumference is worked out at 6.37

We start by finding the side

As a = half circumference = 20 x sin (30) =10 we x2 for full circumference, then divide by pi

10 +10 =20cm  circumference.

20/6.28 =3.1847133758 = radius

we x 2 and find the height

3.1847133758 x 2  = 6.3694267516

rounded to nearest 10th = 6.4 units exact 6.37

We find other measurements before calculating volume.

and b =  √400-√100 = √300

b= 17.32 (height for volume use) or length of right side cylinder

c= 20 hypotenuse.

Volume = πr2h

V= 3.14 * 6.37 * 17.32 =346.43

V=  346.43 cm ^3

V= 346 cm ^3 to nearest 10th

V= 346.43 cm^3

5 0
3 years ago
Find the exact value of cos(sin^-1(-5/13))
son4ous [18]

bearing in mind that the hypotenuse is never negative, since it's just a distance unit, so if an angle has a sine ratio of -(5/13) the negative must be the numerator, namely -5/13.

\bf cos\left[ sin^{-1}\left( -\cfrac{5}{13} \right) \right] \\\\[-0.35em] ~\dotfill\\\\ \stackrel{\textit{then we can say that}~\hfill }{sin^{-1}\left( -\cfrac{5}{13} \right)\implies \theta }\qquad \qquad \stackrel{\textit{therefore then}~\hfill }{sin(\theta )=\cfrac{\stackrel{opposite}{-5}}{\stackrel{hypotenuse}{13}}}\impliedby \textit{let's find the \underline{adjacent}}

\bf \textit{using the pythagorean theorem} \\\\ c^2=a^2+b^2\implies \pm\sqrt{c^2-b^2}=a \qquad \begin{cases} c=hypotenuse\\ a=adjacent\\ b=opposite\\ \end{cases} \\\\\\ \pm\sqrt{13^2-(-5)^2}=a\implies \pm\sqrt{144}=a\implies \pm 12=a \\\\[-0.35em] ~\dotfill\\\\ cos\left[ sin^{-1}\left( -\cfrac{5}{13} \right) \right]\implies cos(\theta )=\cfrac{\stackrel{adjacent}{\pm 12}}{13}

le's bear in mind that the sine is negative on both the III and IV Quadrants, so both angles are feasible for this sine and therefore, for the III Quadrant we'd have a negative cosine, and for the IV Quadrant we'd have a positive cosine.

8 0
3 years ago
Write y-9= -3(x+2) in slope intercept form
klio [65]

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Step-by-step explanation:

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3 years ago
Consider these scenarios. 1. A piano weighs 5.5 × 102 units.   2. A grain of salt weighs 1.02 × 10-3 units.   3. A tractor trail
zhannawk [14.2K]

Answer:

1) pounds

2) grams

3) tons

Step-by-step explanation:

The suitable measurements for the scenarios are:

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2) A grain of salt weighs 1.02 × 10^-3  units

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3) A tractor trailer weighs 8.8 × 10^1 units

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10²g = 1kg

10^-3g = miligrams

10^1 g = decagram

5 0
4 years ago
Read 2 more answers
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