Answer:
Step-by-step explanation:
<u>Given:</u>
<u>Substitute:</u>
into
<u>Swap the sides:</u>
<u />
<u>Divide both sides of the equation by the coefficient of variable:</u>
<u />
<u>Cross out the common factor:</u>
<u />
<u>Find the equation of the function:</u>
<u />
<u>Substitute:</u>
<u />
<u>Calculate the product or quotient:</u>
<u />
Answer:
1/18
Step-by-step explanation:
Change the denominators to 18 to make like denonminators (make sure to multiply the top)
(16/18 - 15/18)
1/18
Answer:
See below. No image this time.
Step-by-step explanation:
1.
- P(2, 8) → P'(-5, 1), which it went 7 units to the left, and 7 units down. Here is the equation: (x - 7, y - 7).
2.
- R(-4, -9) → R'(-4, -2), which went 7 units up. Here is the equation: (x, y + 7).
3.
- M(10, -3) → M'(3, 4), which went 7 units left, 7 units up. Here's the equation: (x - 7, y + 7).
4.
- K(7, 11) → K'(0, 11), which went 7 units left. Here is the equation: (x - 7, y).
There are 3 choices out of 8 that include two tails. 3/8 = .375 = 37.5%
Hope this can help
Answer: The required solution is 
Step-by-step explanation:
We are given to solve the following differential equation :
where k is a constant and the equation satisfies the conditions y(0) = 50, y(5) = 100.
From equation (i), we have
Integrating both sides, we get
![\int\dfrac{dy}{y}=\int kdt\\\\\Rightarrow \log y=kt+c~~~~~~[\textup{c is a constant of integration}]\\\\\Rightarrow y=e^{kt+c}\\\\\Rightarrow y=ae^{kt}~~~~[\textup{where }a=e^c\textup{ is another constant}]](https://tex.z-dn.net/?f=%5Cint%5Cdfrac%7Bdy%7D%7By%7D%3D%5Cint%20kdt%5C%5C%5C%5C%5CRightarrow%20%5Clog%20y%3Dkt%2Bc~~~~~~%5B%5Ctextup%7Bc%20is%20a%20constant%20of%20integration%7D%5D%5C%5C%5C%5C%5CRightarrow%20y%3De%5E%7Bkt%2Bc%7D%5C%5C%5C%5C%5CRightarrow%20y%3Dae%5E%7Bkt%7D~~~~%5B%5Ctextup%7Bwhere%20%7Da%3De%5Ec%5Ctextup%7B%20is%20another%20constant%7D%5D)
Also, the conditions are
and
Thus, the required solution is
