B) The velocity of a car reduced from 50 km/h to 35 km/h over one minute. <span>B) The velocity of a car reduced from 50 km/h to 35 km/h over one minute. </span>
Well, let’s find the initial velocity first:
Vf = Vi + at
0 = Vi - 9.8*2
0 = Vi - 19.6
Vi = 19.6 m/s
We know the final velocity is 0 because when it hits it’s peak, it’s at 0 m/s.
So now use this kinematic equation to find the final position:
Yf = Yi + Vi*t + 1/2a*t^2
Yf = 0 + 19.6(2) - 4.9(2^2)
Yf = 39.2 - 19.6
Yf = 19.6 meters
If you have any questions for how I derived anything, just lemme know. Most of the info requires thinking and imagining of the situation. I assumed you know gravity is 9.8 and you’re expected to assume velocity is 0 at peak height