The independent variable - the order of when they pour the milk (Christie poured milk first then sugar and Tim did the opposite)
The dependent variable - whether the sugar dissolves or not
The constants - 5 teaspoons of sugar, 5 second stir, same coffee
The normal force on the cart is 79.7 N
Explanation:
In order to find the normal force, we have to analyze the forces acting on the cart on the vertical direction.
In the vertical direction, we have the following forces:
- The weight of the cart, downward, of magnitude , where m is the mass of the cart and g is the acceleration of gravity
- The normal force on the cart, upward, we indicate it with N
- The component of the pushing force acting in the vertical direction, downward, of magnitude , where F is the magnitude of the force and is the angle of the force with the horizontal
Therefore, the equation of the forces on the cart in the vertical direction is:
where the net force is zero since the cart is balanced in the vertical direction. We have:
We take the angle as positive since we are already considering the downward direction in the equation.
Substituting and solving for N, we find the normal force:
Learn more about forces:
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Answer:
For and , the expression is satisfied dimensionally.
Explanation:
is a position and has a dimension of length, .
is acceleration which has dimensions of .
is time with dimension of .
Since is dimensionless, we do not factor it into the dimensional equation as below:
Expanding the first term on the right hand side,
Applying the laws of indices,
The index of each fundamental dimension must be equal on both sides.
For ,
For ,
But
Thus, the equation is dimensionally satisfied for the given values of and .
== You're pushing the load <u><em>straight</em></u> along the horizontal surface at a <u><em>constant speed</em></u>.
== The speed and direction of the load are not changing, so there is <u><em>no acceleration.</em></u>
== From Newton's 2nd law of motion, we know that F = m A . Since A=0, F must also be zero. That means <em>NO NET FORCE</em> is acting on the load.
== But how can that be ? You're pushing it with 90 N !
== The NET force is zero. So something else must be pushing the box, also with <em>90 N of force, exactly opposite to YOUR force, </em>and they add up to zero.
== THERE's your force of friction !