Let me try:
Normal force= 169.74N
Coefficient of kinetic friction= 0.577
Explanation
a. For a given inclined plane, normal friction is equal to the force perpendicular to the plane which is equal to
mgcos theta = 20×9.8× cos30 = 169.74N
b. The coefficient of kinetic friction for an inclined plane is given as
tan theta =tan 30 = 0.577
In the graph we can see that that the time at which the particle is farthest from the origin is point B. We know this b<span>ecause it has the biggest value of position. This means that the position-axis value, known also as the x axis, is how far you are away from the origin.</span>
Answer:
v² = u² + 2x²
Explanation:
v² = u² + 2as is only valid for constant acceleration. Here, the acceleration is a function of position. We can find the function of velocity by integrating. Acceleration is the derivative of velocity with respect to time:
a = 2x
dv/dt = 2x
Apply chain rule:
dv/dt = dx/dt × dv/dx
dv/dt = v × dv/dx
Therefore:
v dv/dx = 2x
Separate the variables and integrate:
v dv = 2x dx
½ v² |ᵤᵛ = x² |₀ˣ
½ (v² − u²) = x²
v² − u² = 2x²
v² = u² + 2x²
