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ArbitrLikvidat [17]
3 years ago
15

The acceleration of gravity on Earth is approximately 10 m/s2 (more precisely, 9.8 m/s2). If you drop a rock from a tall buildin

g, about how fast will it be falling after 3 seconds?
Physics
1 answer:
mars1129 [50]3 years ago
8 0

Answer:

30 m/s

Explanation:

Velocity is v_{final}=v_{initial}+at since we know that the initial velocity is 0, and the acceleration is 9.8 \frac{m}{s^2} \approx 10 \frac{m}{s^2} then we also know that time is 3 seconds it follows that: v_{final}=v_{initial}+at=0+10\frac{m}{s^2}*3s=30\frac{m}{s}

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What are the inner planets relative distance from the Sun
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Which of the following objects most likely has a constant speed?
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A car that makes a u turn
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A 1.60 m cylindrical rod of diameter 0.450 cm is connected to a power supply that maintains a constant potential difference of 1
frosja888 [35]

The question is incomplete! Complete question along with answer and step by step explanation is provided below.

Question:

A 1.60 m cylindrical rod of diameter 0.450 cm is connected to a power supply that maintains a constant potential difference of 12.0 V across its ends, while an ammeter measures the current through it. You observe that at room temperature (20.0 ∘C) the ammeter reads 18.4 A , while at 92.0 ∘C it reads 17.4 A . You can ignore any thermal expansion of the rod.

a) Find the resistivity and for the material of the rod at 20° C .

b) Find the temperature coefficient of resistivity at 20° C for the material of the rod.

Given Information:

Room temperature = T₀ = 20° C

Temperature = T = 92° C

Current at 20° C = I₀ = 18.4 A

Current at 92° C = I = 17.4 A

Voltage = V = 12 V

Length = L = 1.60 m

Diameter = d = 0.450 cm = 0.0045 m

Required Information:

Resistivity of the material at 20° C = ρ = ?

Temperature coefficient of resistivity at 20° C = α = ?

Answer:

Resistivity of the material at 20° C = 2.062x10⁻⁶ Ω.m

Temperature coefficient of resistivity at 20° C = 7.986x10⁻⁴ per °C

Explanation:

a) We want to find out the resistivity of the material at 20° C

The resistivity of any material can be found using,

ρ = R₀A/L

Where R₀ is the resistance of the rod at 20° C, A is the area of rod and L is the length of the cylindrical rod.

We also know that area is given by

A = πr²

where r = d/2 = 0.0045/2 = 0.00225 m

A = π(0.00225)²  

A = 5.062⁻⁶ m²

We know that resistance of the material is given by

R₀ = V/I₀

R₀ = 12/18.4

R₀ = 0.6521 Ω

Therefore, the resistivity of the material is

ρ = R₀A/L

ρ = (0.6521*5.062⁻⁶)/1.60

ρ = 2.062x10⁻⁶ Ω.m

b) We want to find out the temperature coefficient of resistivity of the rod at 20° C

The temperature coefficient of resistivity is given by

α = R/R₀ - 1/(T - T₀)

Where R is the resistance of the rod at 90° C

R = V/I

R = 12/17.4

R = 0.6896 Ω

α = R/R₀ - 1/(T - T₀)

α = (0.6896/0.6521) - 1/(92° - 20°)

α = 0.0575/72°

α = 0.000798 per °C

α = 7.986x10⁻⁴ per °C

3 0
3 years ago
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Magnitudes físicas y sus unidades ; poner a que magnitud pertenece
BARSIC [14]

Answer:

1. Energía = 4 J

2. Fuerza = 1,3 N

3. Aceleración = 2 m/s²

4. Masa = 7,1 kg

Explanation:

Magnitudes físicas y sus unidades;

1. Energía = 4 Joules

Energía se puede definir como la habilidad (capacidad) para realizar un trabajo.

2. Fuerza = 1,3 Newton

Fuerza = masa * aceleración

3. Aceleración = 2 m/s²

Aceleración se puede definir como la tasa de cambio de la velocidad de un objeto con respecto al tiempo.

Esto simplemente significa que la aceleración viene dada por la resta de la velocidad inicial de la velocidad final a lo largo del tiempo.

4. Masa = 7,1 Kilograms

La masa se puede definir como una medida de la cantidad de materia de la que se compone un objeto o un cuerpo. La unidad de medida estándar de la masa de un objeto o un cuerpo son los kilogramos.

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