Answer:
The total pressure exerted by mixture of gas is equal to the sum of the partial pressure of individual gases.
Explanation:
According to Dalton law of partial pressure,
The total pressure exerted by mixture of gas is equal to the sum of the partial pressure of individual gases.
Mathematical expression:
P(total) = P₁ + P₂ + .............P(n)
P₁= Partial pressure of one gas
P₂ = Partial pressure of second gas
Pn = Partial pressure of number of gases
For example:
A gaseous mixture consist of He and Ne gas . The pressure exerted by He is 2 atm while neon exerted 4 atm. The total pressure will be:
P(total) = P(He) + P(Ne)
P(total) = 2 atm + 4 atm
P(total) = 6 atm
Answer:
The volume of displaced fluid is equivalent to the volume of an object fully immersed in a fluid.
Answer:
Explanation:
4 = Given data:
Initial volume = 400 mL
Initial pressure = 450 torr
Initial temperature = 210 K
Final temperature = ?
Final volume = 1500 mL
Final pressure = 800 torr
Formula:
P₁V₁/T₁ = P₂V₂/T₂
P₁ = Initial pressure
V₁ = Initial volume
T₁ = Initial temperature
P₂ = Final pressure
V₂ = Final volume
T₂ = Final temperature
Solution:
P₁V₁/T₁ = P₂V₂/T₂
T₂ = P₂V₂ T₁/ P₁V₁
T₂ = 800 torr × 1500 mL × 210 K / 450 torr × 400 mL
T₂ = 252000,000 K / 180000
T₂ = 1400 K
5 = Given data:
Initial volume of gas = 4.5 L
Initial temperature = 25°C (25 + 273 = 298 k)
Final temperature = 25°C×3= 75°C (75+273 = 348 k)
Final volume = ?
Solution:
V₁/T₁ = V₂/T₂
V₁ = Initial volume
T₁ = Initial temperature
V₂ = Final volume
T₂ = Final temperature
Now we will put the values in formula.
V₁/T₁ = V₂/T₂
V₂ = V₁T₂/T₁
V₂ = 4.5 L × 348 K / 298 k
V₂ = 1566 L.K / 298 K
V₂ = 5.3 L
Extra credit:
Given data:
Initial volume = 356 cm³ or 356 mL
Initial pressure = 105000 pa
Initial temperature = 23 °C
Final temperature = ?
Final volume = 560 dL
Final pressure = 36 psi
Formula:
Final volume = 560×100 = 5600 mL
Initial temperature = 23 °C ( 273 + 23 = 296 K)
Final pressure = 36 × 6895 = 248220 Pa
P₁V₁/T₁ = P₂V₂/T₂
P₁ = Initial pressure
V₁ = Initial volume
T₁ = Initial temperature
P₂ = Final pressure
V₂ = Final volume
T₂ = Final temperature
Solution:
P₁V₁/T₁ = P₂V₂/T₂
T₂ = P₂V₂ T₁/ P₁V₁
T₂ = 248220 Pa × 5600 mL × 296 K /105000 pa × 356 mL
T₂ = 411449472,000 K / 37380000
T₂ = 11007.21 K
We can solve this problem using Raoults law. The formula
for Raoults law is:
P_a = X_a * P
where,
P_a = the partial pressure of substance A
X_a = the mole fraction of substance A
P = total pressure
Therefore calculating for P:
P = P_a / X_a
P = 0.580 atm / 0.35
<span>P = 1.657 atm</span>
Answer:
Linoleic acid has 18 carbons in its carbon chain and 2 double bonds, and the first double bond starts at the 6th carbon from the omega end, thus, it is named omega 6.
Explanation:
Fatty acids are carboxilic acids with long chains of carbon (always in even numbers). There are two types of fatty acids: saturated fatty acid s(without double bonds) or unsaturated fatty acids (with double bonds). Unsaturated fatty acids has common names (linolenic acid, palmitic acid, etc.) and the position of the first double bond present in the molecule are indicated with the greek letter omega (counting from the omega extreme, it means the one with metyl radical) . Based 0on that, unsaturated fatty acids are also called omega x, where "x" represents the position of the first double bond. In the present case, the fatty acid that has 18 carbons and two double bonds is commonly named as linoleic acid and taken into account the position of its first double bond (carbon 6) it is also called omega 6.