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BigorU [14]
3 years ago
14

Successive ionization energy for Cu²+​

Chemistry
1 answer:
kogti [31]3 years ago
8 0

Answer:

Here's what I get  

Explanation:

The ionization energy (I) is the energy required to remove an electron from an atom in the gaseous phase.

You can remove electrons in succession and measure the energies required as I₁, I₂, I₃, etc.

Thus, the removal of two electrons from Cu gives you Cu²⁺.

I found the ionization energies of Cu and used them to create those of Cu²⁺ (see table and graph below).

The electron configuration of Cu²⁺ is

Cu²⁺: 1s² 2s²2p⁶ 3s²3p⁶ 3d⁹

You can remove the nine 3d electrons and then there is a sudden jump from I₉ to I₁₀ as you break into the filled [Ar] configuration.

Similarly, there is big jump from I₁₇ to I₁₈ as you break into the filled [Ne] configuration.

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Changing from liquid to gas is a chemical change.<br> True<br> False
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Answer:

This is False

Explanation:

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When you have water and boil it to be a gas, it is still the same matter, just in a different form.

I hope this helps :)

6 0
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The process by which organisms makes more<br> organisms like themselves is called
kondor19780726 [428]

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Reproduction

Explanation:

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The dipole measured for HI is 0.380 D. The bond distance is 161 pm. What is the percent ionic character of the HI bond?
Feliz [49]

Answer:

Percent ionic character of HI bond is 4.91%.

Explanation:

<h3>Given Data:</h3>

Measured Dipole = 0.380D

bond distance = d = 161pm = 1.61*10^-8 cm

<h3>Calculation:</h3>

% ionic character is determined by following equation:

% ionic= (dipole measured/dipole calculated)*100

Now,

Dipole(calc)=qd

Dipole(calc)= (1.6*10^{-19}*3*10^{9})esu  *1.61*10^{-8}cm

(In above step 3*10^8 is multiplied to convert coulomb into esu)

Dipole(calc)=7.728*10^{-18} esu*cm

As,

10^{-18}esu*cm= 1D

So,

Dipole(calc)=7.728D

Now we can % ionic character using above equation:

%ionic=(0.380D/7.728D)*100

% ionic character=4.91%

5 0
4 years ago
In the following reaction, which are the products?
myrzilka [38]

Answer: H2 + MgCl2

Explanation: As they are on the right side of the equation/ are the products being made as a result of the reaction, they are the products.

5 0
3 years ago
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