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Rina8888 [55]
3 years ago
14

Determine whether each of these sets is finite, countably infinite, or uncountable. For those that are countably infinite, exhib

it a one-to-one correspondence between the set of positive integers and that set.
a) the integers greater than 10
b) the odd negative integers
c) the integers with absolute value less than 1,000,000
d) the real numbers between 0 and 2
e) the set A×Z+ where A={2,3}
Mathematics
1 answer:
anzhelika [568]3 years ago
6 0

Answer:

a) Countably infinite

b) Countably infinite

c) Finite

d) Uncountable

e) Countably infinite

Step-by-step explanation:

a) Let S the set of integers grater than 10.

Consider the following correspondence:

f: S\rightarrow \mathbb{Z}^+ defined by f(10+k)=k-1 for k\in\mathbb{Z}^+/\{0\}.

Let's see that the function is one-to-one.

Suppose that f(10+k)=f(10+j) for k≠j. Then k-1=j-1. Thus k-j=1-1=0. Then k=j. This implies that 10+k=10+j. Then the correspondence is injective.

b) Let S the set of odd negative integers

Consider the following correspondence:

f: S\rightarrow \mathbb{Z}^+ defined by f(-(2k+1))=k.

Let's see that the function is one-to-one.

Suppose that f(-(2k+1))=f(-(2j+1)) for k≠j. By definition, k=j. This implies that the correspondence is injective.

c) The integers with absolute value less than 1,000,000 are in the intervals A=(-1.000.000, 0) B=[0, 1.000.000). Then there is 998.000 integers in A that satisfies the condition and 999.000 integers in B that satifies the condition.

d) The set of real number between 0 and 2 is the interval (0,2) and you can prove that the interval (0,2) is equipotent to the reals. Then the set is uncountable.

e) Let S the set A×Z+ where A={2,3}

Consider the following correspondence:

f: S\rightarrow \mathbb{Z}^+ defined by f(2,k)=2k, \;f(3,j)= 2j+1

Let's see that the function is one-to-one.

Consider three cases:

1. f(2,k)=f(2,j), then 2k=2j, thus k=j.

2. f(3,k)=f(3,j), then 2k+1=2j+1, then 2k=2j, thus k=j.

3.  f(2,k)=f(3,j), then 2k=2j+1. But this is impossible because 2k is an even number and 2j+1 is an odd number.

Then we conclude that the correspondence is one-to-one.

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Answer:

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Step-by-step explanation:

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 1 cup of blue paint =  \frac{1}{3} ÷ \frac{1}{5} cup of yellow paint

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3 years ago
40 points urgent really need answer
Kipish [7]

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3 years ago
Solve for x<br> HELLLLP​
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Simplifying

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Reorder the terms:

-15 + 25x = 2y

Solving

-15 + 25x = 2y

Solving for variable 'x'.

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Add '15' to each side of the equation.

-15 + 15 + 25x = 15 + 2y

Combine like terms: -15 + 15 = 0

0 + 25x = 15 + 2y

25x = 15 + 2y

Divide each side by '25'.

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3 years ago
Which of these statements is true for f(x)=(1/10)^x
lana66690 [7]

Step-by-step explanation:

Considering the function

f\left(x\right)=\:\left(\frac{1}{10}\right)^x

Analyzing option A)

Considering the function

f\left(x\right)=\:\left(\frac{1}{10}\right)^x

Putting x = 1 in the function

f\left(1\right)=\:\left(\frac{1}{10}\right)^1

f\left(1\right)=\:\left\frac{1}{10}\right

So, it is TRUE that when  x = 1 then the out put will be f\left(1\right)=\:\left\frac{1}{10}\right

Therefore, the statement that '' The graph contains \left(1,\:\frac{1}{10}\right)  '' is TRUE.

Analyzing option B)

Considering the function

f\left(x\right)=\:\left(\frac{1}{10}\right)^x

The range of the function is the set of values of the dependent variable for which a function is defined.

\mathrm{The\:range\:of\:an\:exponential\:function\:of\:the\:form}\:c\cdot \:n^{ax+b}+k\:\mathrm{is}\:\:f\left(x\right)>k

k=0

f\left(x\right)>0

Thus,

\mathrm{Range\:of\:}\left(\frac{1}{10}\right)^x:\quad \begin{bmatrix}\mathrm{Solution:}\:&\:f\left(x\right)>0\:\\ \:\mathrm{Interval\:Notation:}&\:\left(0,\:\infty \:\right)\end{bmatrix}

Therefore, the statement that ''The range of f(x) is y > \frac{1}{10} " is FALSE

Analyzing option C)

Considering the function

f\left(x\right)=\:\left(\frac{1}{10}\right)^x

The domain of the function is the set of input values which the function is real and defined.

As the function has no undefined points nor domain constraints.

So, the domain is -\infty \:

Thus,

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Therefore, the statement that ''The domain of f(x) is x>0 '' is FALSE.

Analyzing option D)

Considering the function

f\left(x\right)=\:\left(\frac{1}{10}\right)^x

As the base of the exponential function is less then 1.

i.e. 0 < b < 1

Thus, the function is decreasing

Also check the graph of the function below, which shows that the function is decreasing.

Therefore, the statement '' It is always increasing '' is FALSE.

Keywords: function, exponential function, increasing function, decreasing function, domain, range

Learn more about exponential function from brainly.com/question/13657083

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4 years ago
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<h3>How to make a scatter plot?</h3>

To do this, we make use of the following points

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See attachment for the scatter plot.

<h3>The description of a point</h3>

To do this, we make use of the point (12, 190)

This means that the temperature after 12 hours is 190 degrees Celsius

Read more about scatter plots at:

brainly.com/question/13984412

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