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Nastasia [14]
3 years ago
10

Find octal expansion of (B5D)16.

Mathematics
1 answer:
Snowcat [4.5K]3 years ago
5 0

b5d₁₆ = 11×16² + 5×16¹ + 13×16⁰

… = 11×(2×8)² + 5×(2×8)¹ + 13×(2×8)⁰

… = 11×4×8² + 5×2×8¹ + 13×8⁰

… = 44×8² + 10×8¹ + 13×8⁰

… = (40 + 4)×8² + (8 + 2)×8¹ + (8 + 5)×8⁰

… = (5×8 + 4)×8² + (1×8 + 2)×8¹ + (1×8 + 5)×8⁰

… = 5×8³ + 4×8² + 1×8² + 2×8¹ + 1×8¹ + 5×8⁰

… = 5×8³ + 5×8² + 3×8¹ + 5×8⁰

… = 5535₈

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Relations expressed as ordered pairs are?
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3 years ago
Reduce to simplest form. - 3/5 + 1/3
Pani-rosa [81]

Answer: -4/15

Step-by-step explanation: To add these two fractions together,

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In order to get a denominator of 15 in each fraction,

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8 0
3 years ago
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faust18 [17]

6.\\\text{We know}\ 9=3^2.\ \text{Therefore}\\\\9^2=(3^2)^2\\\\\text{use}\ (a^n)^m=a^{nm}\\\\9^2=(3^2)^2=3^{2\cdot2}=3^4\\\\\boxed{3^4=9^2}\\=================

7.\\METHOD\ 1:\\\\\sqrt{7^4}=\sqrt{7^{2\cdot2}}\\\\\text{use}\ (a^n)^m=a^{nm}\\\\=\sqrt{(7^2)^2}\\\\\text{use}\ \sqrt{a^2}=a\ \text{for}\ a\geq0\\\\=\boxed{7^2}\\\\METHOD\ 2:\\\\\text{use}\ a^\frac{m}{n}=\sqrt[n]{a^m}\\\\\sqrt{7^4}=7^\frac{4}{2}=\boxed{7^2}\\=================

8.\\5^a\times5^b=5^{11}\\\\a)\\\text{use}\ a^n\times a^m=a^{n+m}\\\\5^a\times5^b=5^{a+b}\\\\5^{a+b}=5^{11}\Rightarrow a+b=11\\\\11\ \text{is odd. The sum of even and odd is odd. Therefore}\ a\ \text{and}\ b\ \text{can't be even.}\\--------------------\\\\b)\\5\ \text{solutions}\\\\11=5+6\\11=4+7\\11=3+8\\11=2+9\\11=1+10

3 0
3 years ago
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