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3 years ago

What is the correct answer for 5/8+2/5 in fractions and fractions

Mathematics

1 answer:

bezimeni [28]3 years ago

7 0

The answer is 1 1/40 as a mixed fraction! An improper fraction would be 41/40! Hope this picture helps!

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Solve each equation 7:x=2:3

Olenka [21]

7 : x = 2 : 3

- divide 7 by 2.

7/2 = 3.5

- this is the scale factor.

- now multiply this by 3.

3 X 3.5 = 10.5

so, x = 10.5

6 0

3 years ago

If a + b = 15, find the maximum value of a × b

Otrada [13]

Answer: 56

Step-by-step explanation:

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3 years ago

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Jack spends 1 1/2 times as long on his homework as Jill.

Minchanka [31]

Answer:

12 3/4 hours

Step-by-step explanation:

Jack spends 1 1/2 times as long on his homework as Jill .

Jill spends 8 1/2 in doing his home work .

Time spent by jack in doing his homework is jacks time multiplied by Jill’s

That’s

1 1/2 x 8 1/2

Change to improper fractions.

We have,

3/2 x 17/2

Multiply through

51/4 = 12 3/4

Jack spends 12 3/4 hours in doing his homework

4 0

3 years ago

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Round the following as specified. 153.38519 to the nearest thousandth.

In-s [12.5K]

Answer:

153.3852

Step-by-step explanation:

After the decimal, you count the places. 3 is in the ones place, 8 in the tenths, 5 in the hundreths, and 1 in the thousandths. The thousandths place is what we are rounding, so we look at the next number, 9, which tells us to round the 1 up to 2

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3 years ago

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Please help me!!!!! Its exponents!

Vlad [161]

Answer:

Please check the answer below.

Step-by-step explanation:

Considering the statement

$2^?$

If $?$ is an whole number.

Set of whole number = {0, 1, 2, 3, ....}

Example 1:

When statement is always true:

For x > 0, the statement will be always be true.

Lets put x = 1

$2^1$

2 < 3

So, the statement is true when x = 1

Example 2:

When statement is always true:

For x > 0, the statement will be always be true.

Lets put x = 2

$2^2$

4 < 9

So, the statement is true when x = 2

Example 3:

When statement is Never true:

For x = 0, the statement will never be true.

Lets put x = 0

$2^0$

$\mathrm{Apply\:rule}\:a^0=1,\:a\ne \:0$

$2^0=1, 3^0=1$

So,

$1$

Therefore, the statement is False.

Keywords: exponential number, whole number

Learn more about exponential number from brainly.com/question/3141841

#learnwithBrainly

6 0

3 years ago