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3 years ago

Simplify the number 8 ^2/3

2 answers:

8 0

Eight to the third power is 8X8X8 and that is equal to 512 8X8 is 64 that’s eight to the second hope I helped and mark brainliest

pishuonlain [190]3 years ago

5 0

Answer:

te ayudara en las ecuaciones

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Translate this phrase into an algebraic expression. Eight more than the product of 8 and a number Use the variable n to represen

Anni [7]

Answer:

8n + 8

Step-by-step explanation:

We already know that n is the unknown number. Product means multiplying, so you multiply 8 by the unknown number. More than means adding, so you add 8 to the product of 8n.

4 0

3 years ago

How do you create and solve equations in one variable given a real-world situation?

kkurt [141]

Answer:

by finding something to factor it by

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3 years ago

What is the answer to the picture I have attached

vlabodo [156]

Answer:

Step-by-step explanation:

i got it right

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3 years ago

How to find it is related to the opposite angle in a cyclic quadrilateral is equal to 180 degeres

lorasvet [3.4K]

Answer: The measure of ∠BEF=110°.

Step-by-step explanation:

Given: In cyclic quadrilateral ABCD, ∠C = 110°

Then, ∠A+∠C=180° [The sum of opposite angles in a cyclic quadrilateral is 180 degrees.]

⇒ ∠A+ 110°=180°

⇒ ∠A = 180° - 110°

⇒ ∠A = 70°

In cyclic quadrilateral ABEF,

∠A+∠E=180° [The sum of opposite angles in a cyclic quadrilateral is 180 degrees.]

⇒ 70° + ∠E=180°

⇒∠E=110°

Hence, the measure of ∠BEF=110°.

5 0

3 years ago

Find the solutions to the following linear-quadratic systems algebraically. Select the ordered pair that is one of the correct s

Ghella [55]

Answer:

(-2, 6)

Step-by-step explanation:

we have

$y=x^{2} +3x+8$ ----> equation A

$y=2x+10$ ----> equation B

equate equation A and equation B

$x^{2} +3x+8=2x+10$

$x^{2} +3x+8-2x-10=0$

$x^{2} +x-2=0$

The formula to solve a quadratic equation of the form

$ax^{2} +bx+c=0$

is equal to

$x=\frac{-b\pm\sqrt{b^{2}-4ac}} {2a}$

in this problem we have

$x^{2} +x-2=0$

$a=1\\b=1\\c=-2$

substitute in the formula

$x=\frac{-1\pm\sqrt{1^{2}-4(1)(-2)}} {2(1)}$

$x=\frac{-1\pm\sqrt{9}} {2}$

$x=\frac{-1\pm3} {2}$

$x=\frac{-1+3} {2}=1$

$x=\frac{-1-3} {2}=-2$

Find the values of y

For x=1

$y=2(1)+10=12$

For x=-2

$y=2(-2)+10=6$

therefore

The solutions are (1,12) and (-2,6)

3 0

3 years ago