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jasenka [17]
3 years ago
7

Set up, but do not evaluate, an integral for the volume of the solid obtained by rotating the region bounded by the given curves

about the specified axis.
y = sqrt(x), y = x^2; about y = 2
or y = \sqrt{x}, y = x^2; about y = 2

Mathematics
1 answer:
Radda [10]3 years ago
4 0
A washer has outer radius 2-x^2 and inner radius 2 - \sqrt{x}

\displaystyle V = \int_0^1 \pi\Big[ \left( 2 - x^2 \right)^2 - \left( 2 - \sqrt{x}\right)^2\Big] dx

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Janine inflated a ball to a radius of 18 cm and another ball to a radius of 12 cm.
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Volume of a ball = (4/3)πr³

When r = 18cm, V = (4/3)×3.14×18³ =24416.64 cm³
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3 0
4 years ago
Read 2 more answers
Please help me. I don’t understand this at all...
mylen [45]
Problem 1

With limits, you are looking to see what happens when x gets closer to some value. For example, as x gets closer to x = 2 (from the left and right side), then y is getting closer and closer to y = 1/2. Therefore the limiting value is 1/2

Another example: as x gets closer to x = 4 from the right hand side, the y value gets closer to y = 4. This y value is different if you approach x = 0 from the left side (y would approach y = 1/2)

Use examples like this and you'll get the results you see in "figure 1"

For any function values, you'll look for actual points on the graph. A point does not exist if there is an open circle. There is an open circle at x = 2 for instance, so that's why f(2) = UND. On the other hand, f(0) is defined and it is equal to 4 as the point (0,4) is on the function curve.

=======================================================

Problem 2

This is basically an extension of problem 1. The same idea applies. See "figure 2" (in the attached images) for the answers. 

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3 years ago
Which graph represents y as a function of x? <br> A) A <br> B) B <br> C) C <br> D) D
Arlecino [84]

Answer:

where is the graph if you can put it i will give you the answer

Step-by-step explanation:

8 0
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