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3 years ago

Consider the expression? Please help me !

Mathematics

2 answers:

Arada [10]3 years ago

8 0

Answer:

sqrt(-8x+5)

Step-by-step explanation:

(5-8x)

-----------------

sqrt(-8x+5)

We need to rationalize the denominator

(5-8x) sqrt(-8x+5)

----------------- * ---------------

sqrt(-8x-5) sqrt(-8x+5)

(5-8x) sqrt(-8x+5)

----------------- * ---------------

(-8x+5)

The first term cancels

sqrt(-8x+5)

dmitriy555 [2]3 years ago

4 0

Answer:

Second option

Step-by-step explanation:

The radical represents the square root, i.e power ½

(5 - 8x) ÷ (5 - 8x)^½

(5 - 8x)^(1-½)

(5 - 8x)^½

(-8x + 5)^½ (just a rearrangement)

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I need help from uh all..

DanielleElmas [232]

Answer:

Step-by-step explanation:

Given expression is,

$\text{cot}A=\frac{1}{2}(\text{cot}\frac{A}{2}-\text{tan}\frac{A}{2})$

To prove this identity we will take the right side of the identity,

$\frac{1}{2}(\text{cot}\frac{A}{2}-\text{tan}\frac{A}{2})=\frac{1}{2}(\frac{1}{\text{tan}\frac{A}{2}}-tan\frac{A}{2})$

$=\frac{1}{2}(\frac{1-\text{tan}^2\frac{A}{2}}{tan\frac{A}{2}})$

$=\frac{1}{2}[\frac{2(1-\text{tan}^2\frac{A}{2})}{2tan\frac{A}{2}}]$

$=\frac{1}{2}(\frac{2}{\text{tan}A} )$ [Since $\text{tan}A=\frac{2\text{tan}\frac{A}{2}}{1-\text{tan}^2\frac{A}{2}}$ ]

= cot A

Hence right side of the equation is equal to the left side of the equation.

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3 years ago