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3 years ago

Consider the expression? Please help me !

Mathematics

2 answers:

Arada [10]3 years ago

8 0

Answer:

sqrt(-8x+5)

Step-by-step explanation:

(5-8x)

-----------------

sqrt(-8x+5)

We need to rationalize the denominator

(5-8x) sqrt(-8x+5)

----------------- * ---------------

sqrt(-8x-5) sqrt(-8x+5)

(5-8x) sqrt(-8x+5)

----------------- * ---------------

(-8x+5)

The first term cancels

sqrt(-8x+5)

dmitriy555 [2]3 years ago

4 0

Answer:

Second option

Step-by-step explanation:

The radical represents the square root, i.e power ½

(5 - 8x) ÷ (5 - 8x)^½

(5 - 8x)^(1-½)

(5 - 8x)^½

(-8x + 5)^½ (just a rearrangement)

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3. Describe the type of transformation used to produce

earnstyle [38]

Answer:

Reflection over the x- axis

Step-by-step explanation:

6 0

2 years ago

Solve by factoring square roots x^2 -49=0

aliina [53]

Answer:

X=7

Step-by-step explanation:

X = SQRT(49)

X = 7

Best regards

4 0

3 years ago

Maria practice the piano 5/6 of an hour everyday. How many hours does she practice in 4 days

S_A_V [24]

Answer:
10/3 hours

Explanation:
If Maria practices 5/6 hours a day, then she practices (5/6)(4) hours in 4 days.

(5/6)(4)=20/6

20/6 can be simplified to 10/3 hours.

I hope this helps!

3 0

3 years ago

Based on the information below, choose the correct answers.

lozanna [386]

Since there are 120 payment and the total interest paid was $ 14,644.95. so the average monthly interest can be calculated by:

Average monthly interest = $ 14,644.95 / 120

Average monthly interest = $ 122.04

% total interest = ($ 14,644.95) / $ 39,644.95 x 100

% total interest =36.94 %

8 0

3 years ago

How are percent transmittance and absorbance related algebraically?

statuscvo [17]

Answer:

So, if all the light passes through a solution without any absorption, then absorbance is zero, and percent transmittance is 100%. If all the light is absorbed, then percent transmittance is zero, and absorption is infinite.

Absorbance is the inverse of transmittance so,

A = 1/T

Beer's law (sometimes called the Beer-Lambert law) states that the absorbance is proportional to the path length, b, through the sample and the concentration of the absorbing species, c:

A ∝ b · c

As Transmittance, $T =\dfrac{P}{P_0}$

% Transmittance, $\%T=100\times T$

Absorbance,

$A=\log_{10} \dfrac{P_0}{P}\\\\A =\log_{10}\times \dfrac{1}{T}\\\\A=\dfrac{\log_{10} 100}{\%T}\\\\A=(2 - log_{10})\times \%T$

Hence, $A=\log_{10}\times \dfrac{1}{T}$ is the algebraic relation between absorbance and transmittance.

8 0

3 years ago