Answer and explanation.
1. The genotype of a male with red-green color blindness is XcY.
2. The genotype of a female who is not color-blind but is a carrier is XcXC. She carries the color-blind allele but is not dominat, so she is not affected by it.
3. Yes, a female can have red-green color blindness, if her two X chromosomes are cX (recessive), she will have red-green color blindness. In other words, if the two X chromosomes carry the allele for color-blindness she will be affected by it.
4. Possible genotypes are Cc, CC, Cc, and CC. or as it is in the Punnet square XcXc, XcY, XCXc, XCY.
<u> ║ Xc ║ Y</u>
<u> Xc ║ XcXc ║ XcY </u>
<u> XC ║ XCXc║ XCY </u>
5. The female children will be carriers of the color-blind allele becaus one of her two X chromosomes, has the recessive allele for color-blind while the other X chromosome has not the allele for color-blindness.
6. None of the male children will be color-blindness because the allele for color-blindness is carried by the X chromosome of the father and they inherit the X chromosome from the mother, who is color-blind free.