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Neko [114]
3 years ago
14

Solve the following equation: 2 1/3= -9m

Mathematics
2 answers:
otez555 [7]3 years ago
7 0
M= -7/27
I think that's correct
Anit [1.1K]3 years ago
6 0
2 1/3=-9m
divide 2 1/3 by -9
the answer is m=-3 6/7 or -27/7
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the area of a bathroom floor measures 3 yards by 3 yards and each custom tile that makes up the flooring is 1 1/2 square yards.
wel

Using the area, the number of tiles needed to cover the floor is 6.

<h3>What is area?</h3>

The area is the region bounded by the shape of an object.

Therefore, the bathroom floor measures 3 yards by 3yards.

Hence the area of the bathroom floor can be calculated as follows;

area of the bathroom floor = 3 × 3

area of the bathroom floor = 9 yards²

The area of the custom tiles that makes the flooring is 1 1  /2 square yards.

Hence,

number of tiles needed to cover the floor = 9 ÷ 3  /2

number of tiles needed to cover the floor = 9 × 2  / 3

number of tiles needed to cover the floor = 18 / 3

number of tiles needed to cover the floor = 6

learn more on area here: brainly.com/question/946354

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4 0
1 year ago
How is 5-2 different from 5 + ( - 2)
WITCHER [35]
They equal the same amount (3) but are written out in different ways.
5 0
3 years ago
Read 2 more answers
1. Find domain of the function, = ln(2 − 6 − 55).
Bingel [31]
Domain of a function

We want to find the domain of the following function:

=ln\mleft(^2-6-55\mright)

This means that we want to find the x-values that it can take.

<h2>STEP 1: analyzing the simplies form of the function</h2>

Let's analyze the simpliest form of the function:

=ln(x)

Its graph is:

Then, for the simpliest form of the function, the x-values can only be higher than 0.

This means that its domain is

domain = x > 0

<h2>STEP 2: domain of the given function</h2>

Based on the above we can deduce that for the <em>ln(x)</em> function, what is inside the parenthesis should be higher than 0 on this kind of functions.

This is that for

=ln\mleft(^2-6-55\mright)

then

^2-6-55>0<h2>STEP 3: finding the x values that make x²-6x-55>0 (factoring)</h2>

In order to find the values of x that make

^2-6-55>0

we must factor it.

We want to find a pair of numbers that when multiplied give the last term (-55) and when added together give the second term (-6).

For the last term of the polynomial: -55, we have that

(-5) · 11 = 55

5 · (-11) = 11

If we add them:

-5 + 11 = 6

5 - 11 = -6

The pair of numbers that when multiplied give the last term (-55) and when added together give the second term (-6), are: 5 and -11

We use them to factor the polynomial:

^2-6-55=(x+5)(x-11)

Then,

(x+5)(x-11)>0<h2>STEP 4: finding the x values that make (x+5)(x-11)>0 (factoring)</h2>

In order to find them, we are going to separate the factors (x+5) and (x-11) and analyze when they are positive or negative:

Combining them:

Since we are going to multiply both factors:

(x+5)(x-11)

We use the diagram to analyze the sign of their product:

Then

(x+5)(x-11)>0

when x < -5 and when x > 11. This is the domain.

Therefore, expressed in set notation:

domain = {x|x∈(-∞, -5)∪(11, ∞)}

<h2>Answer: domain = {x | x ∈ (-∞, -5)∪(11, ∞)}</h2>

5 0
1 year ago
In △ABC, m∠ABC=40°, BL (L∈AC ) is the angle bisector of ∠
ira [324]

check the picture below.


M is perpendicular to AB and ∈ AB, and stemming from point L.


N is perpendicular to BC and ∈ BC, and stemming from point L as well.


BL is the bisector, that means the angle at verte B, gets cut into two equal halves.


now, we know what ∠CLN =3∠ALM, namely that ∠CLN is 3 times greater than ∠ALM.


so, once the bisector kicks in, you get two angles of 20° each, the angles at M are 90° each and the angles at N are 90° each as well, that pretty much narrows down what the missing angle is in triangles MBL and NBL, so is 70°.


now, the little sliver angles at CLN and ALM are on a 3:1 ratio, so, the flat-line of AC affords us 180°, subtract the 140°, so CLN and ALM will have to share only the remaining 40°, and they have to do so on a 3:1 ratio, that leaves us with, notice the blue angles.


now, from the triangles ALM and CLN, you can pretty much tell what the missing angle is, and those are the values for angles A and C.


Read more on Brainly.com - brainly.com/question/6781441#readmore

8 0
3 years ago
Find the cosine of ∠J.
Lelu [443]

Answer:

\cos =  \frac{base}{hypotenuse}  =   \\ \cos(j)  =  \frac{ \sqrt{29} }{ \sqrt{94} }    =   \sqrt{ \frac{29}{94} }  \\ answer =  \sqrt{ \frac{29}{94} }

4 0
3 years ago
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