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sashaice [31]
3 years ago
7

How am I suppose to do my challenges if nothing shows up

Mathematics
2 answers:
lord [1]3 years ago
4 0
I wonder the same thing
Natasha_Volkova [10]3 years ago
4 0

Answer:

umm i dont know ask them oop my fire alarm going off bye

Step-by-step explanation:

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Pls help with my homework I need help
shusha [124]

Answer:

tan G = 1.6071

Step-by-step explanation:

tan G = 45/28

tan G = 1.6071

6 0
3 years ago
I have 2 questions.
frosja888 [35]
I dont know the first answer but the 2nd is dad
6 0
3 years ago
Read 2 more answers
Round 187.890 to the nearest 10 000
stellarik [79]

Answer:

190,000

190,000

190,000

Step-by-step explanation:

190,000

190,000

6 0
3 years ago
I've been having problems with this for a while...
Rina8888 [55]
Like all problems that involve images within the question, we should definitely try to draw this out. In the picture above, I have done this.

Now, we can see that this is just a simple proportion problem. For every 2.5 cm of height of the flower, we are 2 cm from the opening, or aperture. For every 20 cm of height, how far are we? We can set up the problem like this:

20 ............2.5
-------- = ---------
...x ............. 2

where x is the unknown distance to the aperture from the flower. Now, we just need to get x by itself. A typical way of solving something like this is by doing "butterfly multiplication" which is really just a shortcut haha. Anyway, I can rewrite that equation ^ as:

20×2 = 2.5 × x

Then, to solve for x, we would divide both sides by 2.5. (If you don't know why that is, please let me know and I'll elaborate).

We would then have:

20×2
------- = x
2.5

Which then simplifies to:

x = 16

Try using the same logic for your second question, and if you get stuck, I'd be happy to help! please let me know if any of this doesn't make sense. :)

3 0
4 years ago
A rectangles length is 2 meters greater than its width if the e perimeter is greater than 112 what is the rectangles possible wi
pishuonlain [190]

Answer:

Step-by-step explanation:

Perimeter of a rectangle = 2(L +W)        

Given L = W + 2      and the perimeter is greater than 112 meters?

  P rect    <   2(L +W)        L = W + 2

  P rect    <   2(W + 2 +W)

                <   2(2W+2)

  112         <     4W + 4        solve for W

(112 - 4)/4  <   (4W +4 - 4)/4              

108/4       <   (4W + 0)/4

       27     <    W              

      the width has to be greater than 27 meters

   

5 0
3 years ago
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