The insurance period must be chosen so that the probability of a microchip failure within that period is 4%. Reference to a standard normal distribution table shows that the z-score for a cumulative probability of 4% is -1.75.
Let the insurance period be X months:
-1.75 = (X - 93)/3.8
-6.65 = X - 93
X = 83.35 months.
The answer is 83.35 months.
93% of 149
10% of 149 = 14,9
93% of 149 > 90% of 149
93% of 149 > 149 - 14,9 ≈ 149-15≈134
> 134
⇒ the answer is D
I'm pretty sure this is correct
I believe that B is the answer bc -2-1 is -3 but with absolute value it it's 3, whish is the correct distance
