Yeah, x= 7/2 and y= -5/2
Please mark as brainliest and I hope this helps
Isn't this a subtraction problem, not a multiplication problem?
If John starts out with 20 fish and lets 6 go, he still has (20-6), or 14, fish.
Answer:
-1
Step-by-step explanation:
Answer:
No real roots
Step-by-step explanation:
Given
7x² + 5x + 1 = 0 ← in standard form
with a = 7, b = 5, c = 1
To determine the nature of the roots use the discriminant
Δ = b² - 4ac
• If b² - 4ac > 0 then roots are real and distinct
• If b² - 4ac = 0 then roots are real and equal
• If b² - 4ac < 0 then the roots are not real
Here
b² - 4ac = 5² - (4 × 7 × 1) = 25 - 28 = - 3
Thus the 2 roots are not real
Answer: 3H+4C<_ 30
The coefficients of the variables H and C represent the number of batteries each toy helicopter and each toy car uses.
Step-by-step explanation:
Each toy helicopter uses 3 batteries, and each toy car uses 4 batteries.
Now let's check whether Vugar has enough batteries for 5 toy helicopters and 4 toy cars. To do this, we substitute H=5 and C= 4 in the given inequality:
Does Vugar have enough batteries to play with 5 toy helicopters and 4 toy cars?
No, because if you plug in the value for H and C:
3H + 4C<_ 30
3(5) + 4(4) <_30
15 + 16 <_ 30
31 <_ 30; false
Since the inequality is false, Vugar does not have enough batteries to play with 555 toy helicopters and 444 toy cars.
Each toy helicopter uses 333 batteries, and each toy car uses 444 batteries.
No, Vugar does not have enough batteries to play with 555 toy helicopters and 444 toy cars.
