X = y2 is the equation for it just plug in the numbers
Answer: 0.75
Step-by-step explanation:
Given : Interval for uniform distribution : [0 minute, 5 minutes]
The probability density function will be :-

The probability that a given class period runs between 50.75 and 51.25 minutes is given by :-
![P(x>1.25)=\int^{5}_{1.25}f(x)\ dx\\\\=(0.2)[x]^{5}_{1.25}\\\\=(0.2)(5-1.25)=0.75](https://tex.z-dn.net/?f=P%28x%3E1.25%29%3D%5Cint%5E%7B5%7D_%7B1.25%7Df%28x%29%5C%20dx%5C%5C%5C%5C%3D%280.2%29%5Bx%5D%5E%7B5%7D_%7B1.25%7D%5C%5C%5C%5C%3D%280.2%29%285-1.25%29%3D0.75)
Hence, the probability that a randomly selected passenger has a waiting time greater than 1.25 minutes = 0.75
Answer:
(4 * 5)^3 ;
8000
Step-by-step explanation:
Andre's statement :
Multiply 4 by 5 = 4 * 5 = 20
Cube the result = 20³
The equal expression from the option :
A.) (4 * 5)^3
Also, (4 * 5)^3 = 20^3 = 20 * 20 *20 = 8000
Answer:
none of them
Step-by-step explanation:
Answer:
Question is not clear please post question clearly lots of question marks.