y = 9ln(x)
<span>y' = 9x^-1 =9/x</span>
y'' = -9x^-2 =-9/x^2
curvature k = |y''| / (1 + (y')^2)^(3/2)
<span>= |-9/x^2| / (1 + (9/x)^2)^(3/2)
= (9/x^2) / (1 + 81/x^2)^(3/2)
= (9/x^2) / [(1/x^3) (x^2 + 81)^(3/2)]
= 9x(x^2 + 81)^(-3/2).
To maximize the curvature, </span>
we find where k' = 0. <span>
k' = 9 * (x^2 + 81)^(-3/2) + 9x * -3x(x^2 + 81)^(-5/2)
...= 9(x^2 + 81)^(-5/2) [(x^2 + 81) - 3x^2]
...= 9(81 - 2x^2)/(x^2 + 81)^(5/2)
Setting k' = 0 yields x = ±9/√2.
Since k' < 0 for x < -9/√2 and k' > 0 for x >
-9/√2 (and less than 9/√2),
we have a minimum at x = -9/√2.
Since k' > 0 for x < 9/√2 (and greater than 9/√2) and
k' < 0 for x > 9/√2,
we have a maximum at x = 9/√2. </span>
x=9/√2=6.36
<span>y=9 ln(x)=9ln(6.36)=16.66</span>
the
answer is
(x,y)=(6.36,16.66)
Answer:
The height of the water = 6.2 in. to the nearest tenth
Step-by-step explanation:
∵ The rate of flows of water into the tank = 8000 in.³/min.
∴ The volume of the water in the tank after 10 min. = 8000 × 10 = 80000 in.³
∵ The water take the shape of the tank
∴ The height of the water = volume of water ÷ Area of the base of the tank
∵ The tank is cylinder with diameter 128 in. and height 72 in.
∴ The area of the base of the tank = π(128/2)²
∴ The height of the water = 
∴ The height of the water = 6.2 in. to the nearest tenth
Answer:
Step-by-step explanation:
Day 1 = 2 birds
day 2 = 3 birds
day 3 = 9 birds
day 4 = 8 birds
day 5 = 1 bird
On day 1 the points are (1,2)
On day 5 the points are (5,1)
(I am picking these for the points because I don't know your options for the selecting area.)
we use this formula y2-y1/x2-x1
2-5/1-1
3/0
our answer is infinite which is the relation and this is an infinite function
Answer:
Sofia measures the length of her car as 16 feet.
What is the greatest possible error?
<h2> ⇒ 0.5 feet
</h2>
What is the margin of error?
<h2> ⇒ 15.5 TO ⇒ 16.5 feet</h2>
Step-by-step explanation:
You would need to remove (-2, 1)