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3 years ago

Construct two chords BC and DE that intersect in the interior of a circle at point F

Mathematics

1 answer:

joja [24]3 years ago

6 0

The diagram has been inserted below.

There is a circle.

Two chords, BC and DE intersect at a point F inside the circle.

A chord of a circle is a straight line segment whose endpoints both lie on the circle.

To know the chord length, we need to know the radius or central angle or the perpendicular distance to the center.

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If a 12-student class averaged 90 on a test, and a 20-student class averaged 80 on the test, then all 32 students averaged

Alexxx [7]

Let the marks of the students in class 1 be

$m_1, m_2, ....., m_1_2$

the average of these 12 marks is 90, so

$\frac{m_1+ m_2+ .....+ m_1_2}{12}=90$

which means

$m_1+ m_2+ .....+ m_1_2=90*12=1080$

similarly, let $n_1, n_2, ....., n_2_0$ be the marks of the students in the second class,

so $\frac{n_1+ n_2+ ..... n_2_0}{20}=80$

which means $n_1+ n_2+ ..... n_2_0=80*20=1600$

The 32 students averaged:

$\frac{(m_1+ m_2+ .....+ m_1_2)+(n_1+ n_2+ ..... n_2_0)}{12+20}= \frac{1080+1600}{32}= \frac{2680}{32}= 83.75$

5 0

3 years ago

Read 2 more answers

Clara pays $76 for 8 guitar lessons. How much would 10 guitar lessons cost? Enter your answer in the box.

WARRIOR [948]

You would divide 76 by 8. That would give you 9.5. Then you multiply by 10 and that gives you 95. Hope this helps (;

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3 years ago

Has one negative and one positive coefficient Simplifies to 5x + 12

rosijanka [135]

Answer:

Step-by-step explanation:

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2 years ago

Find the slope(6,8) and (9,10)

USPshnik [31]

name the points

a=(x1,y1) b=(x2,y2)

a=(6,8) b=(9,10)

use the slope formula

$m=\frac{y2-y1}{x2-x1}$

replace

$\begin{gathered} m=\frac{10-8}{9-6} \\ m=\frac{2}{3} \end{gathered}$

answer= The slope is equal to 2/3

a=(9,10) b=(6,8)

using the formula

$\begin{gathered} m=\frac{y2-y1}{x2-x1} \\ m=\frac{8-10}{6-9} \\ m=\frac{-2}{-3}=\frac{2}{3} \end{gathered}$

slope will also be 2/3

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8 months ago

What is the discriminant <br><br> 3g^2+10= -15g

Ilia_Sergeevich [38]

$\bf 3g^2+10=-15g\implies 3g^2+15g+10=0
\\\\\\
\begin{array}{llcccll}
& 3g^2& +15g& +10\\
&\uparrow &\uparrow &\uparrow \\
&a&b&c
\end{array}
\\\\\\
discriminant\implies b^2-4ac\implies 15^2-4(3)(10)$

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3 years ago