Comment
I'm going to take a guess at this and say what you meant is 2401 = 7^(6 - 2x)
Step One
Find out the power of 7 that will equal 2401.
You could do it like this.
7^y = 2401 and just guess at some values.
y 7^y
1 7
2 49
3 7 * 7 * 7 = 343
4 7 * 7 * 7 * 7 = 2401 So the answer is 4
7^4 = 2401
Step 2
Equate the powers.
2401 = 7^(6 - 2x)
7^4 = 7^ (6 - 2x)
4 = 6 - 2x Subtract 6 from both sides.
4 - 6 = - 2x
-2 = - 2x divide by - 2
-2/-2 = x
x = 1 <<<<<<<<<<<<<answer
Answer:
Approximately 4,000 times
Step-by-step explanation:
If you're flipping a coin to get 4 heads out of 10 and you times it by 10,000 then you would have a probable win rate of 4,000.
Answer:
8
Step-by-step explanation:
Check the picture below on the left-side.
we know the central angle of the "empty" area is 120°, however the legs coming from the center of the circle, namely the radius, are always 6, therefore the legs stemming from the 120° angle, are both 6, making that triangle an isosceles.
now, using the "inscribed angle" theorem, check the picture on the right-side, we know that the inscribed angle there, in red, is 30°, that means the intercepted arc is twice as much, thus 60°, and since arcs get their angle measurement from the central angle they're in, the central angle making up that arc is also 60°, as in the picture.
so, the shaded area is really just the area of that circle's "sector" with 60°, PLUS the area of the circle's "segment" with 120°.

![\bf \textit{area of a segment of a circle}\\\\ A_y=\cfrac{r^2}{2}\left[\cfrac{\pi \theta }{180}~-~sin(\theta ) \right] \begin{cases} r=radius\\ \theta =angle~in\\ \qquad degrees\\ ------\\ r=6\\ \theta =120 \end{cases}](https://tex.z-dn.net/?f=%5Cbf%20%5Ctextit%7Barea%20of%20a%20segment%20of%20a%20circle%7D%5C%5C%5C%5C%0AA_y%3D%5Ccfrac%7Br%5E2%7D%7B2%7D%5Cleft%5B%5Ccfrac%7B%5Cpi%20%5Ctheta%20%7D%7B180%7D~-~sin%28%5Ctheta%20%29%20%20%5Cright%5D%0A%5Cbegin%7Bcases%7D%0Ar%3Dradius%5C%5C%0A%5Ctheta%20%3Dangle~in%5C%5C%0A%5Cqquad%20degrees%5C%5C%0A------%5C%5C%0Ar%3D6%5C%5C%0A%5Ctheta%20%3D120%0A%5Cend%7Bcases%7D)