We determined that f(y1, y2) = 6(1 − y2), 0 ≤ y1 ≤ y2 ≤ 1, 0, elsewhere is a valid joint probability density function. (a) Find
E(Y1|Y2 = y2). E(Y1|Y2 = y2) = (b) Use the answer derived in part (a) to find E(Y1). (Compare this with E(Y1) found using the marginal density function f1(y1) = 3(1 − y1)2.) E(Y1) =
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A quadratic function models the profit of the company and the maximum/minimum value of the quadratic function occurs on its vertex.
The given function is:
The equation is already in standard form, the vertex of the parabola as seen from the equation is (5,12)
This mean if the company sets the price of socks to $5 they will earn a maximum profit which is $ 12 million
The given function is:
The equation is already in standard form, the vertex of the parabola as seen from the equation is (5,12)
This mean if the company sets the price of socks to $5 they will earn a maximum profit which is $ 12 million