Solve for d:
(3 (a + x))/b = 2 d - 3 c
(3 (a + x))/b = 2 d - 3 c is equivalent to 2 d - 3 c = (3 (a + x))/b:
2 d - 3 c = (3 (a + x))/b
Add 3 c to both sides:
2 d = 3 c + (3 (a + x))/b
Divide both sides by 2:
Answer: d = (3 c)/2 + (3 (a + x))/(2 b)
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Solve for x:
(3 (a + x))/b = 2 d - 3 c
Multiply both sides by b/3:
a + x = (2 b d)/3 - b c
Subtract a from both sides:
Answer: x = (2 b d)/3 + (-a - b c)
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Solve for b:
(3 (a + x))/b = 2 d - 3 c
Take the reciprocal of both sides:
b/(3 (a + x)) = 1/(2 d - 3 c)
Multiply both sides by 3 (a + x):
Answer: b = (3 (a + x))/(2 d - 3 c)
The ratios as fractions are 6/8 and 9/11.
Since they are not compare because they have different denominators you must find the Least Common Multiple of the two fractions.
Since 8 and 11 both can go into 88, we can use that as our denominator.
6/8 times 11/11 equals 66/88 and 9/11 times 8/8 equals 72/88.
66/88 is less than 72/88.
Therefor, Mix B is the reddest mixture.
Hope this helped!! :)
This works out beautifully. You COULD use long division here, but since your numerator is a quadratic, your first instinct should be to try and factor it. If you factor it, it works out to be (x - 3)(x + 2). Now it just so happens that when you do that, the (x - 3) in the numerator will cancel with the (x - 3) in the denominator leaving you with one sad and lonely (x + 2) as your answer.
You're asking for three consecutive odd numbers, then
Let, the numbers = x, x+2, x+4
It is given that, x + x+2+ x+4 = -27
3x + 6 = -27
3x = -27 - 6
x = -33/3
x = -11
Then, x+2 = -9 & x+4 = -7
In short, Your Numbers would be: -7, -9,-11
Hope this helps!
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