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serg [7]
3 years ago
5

There are 120 people at a party 1/3 leave work out the number of people still at the party

Mathematics
2 answers:
Tpy6a [65]3 years ago
7 0

Answer:

80

Step-by-step explanation:

1/3 of 120 is 40

If 40 leave

People left in party=120-40=80

Anna007 [38]3 years ago
3 0

Answer: Idk da anser  to tis kestion, but I gtta tll u that ma grandm ate an egg with Ketchup and wit sum nuttella on it.

Step-by-step explanation:

1+1=5

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10. 10
11. -2.8




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Factor the following polynomial completely 21x ^ 5 * y ^ 4 - 18x ^ 7 * y ^ 3 + 15x ^ 2 * y ^ 5
tester [92]

Answer:

21x^5y^4-18x^7y^3+15x^2y^5\\3x^2y^3(7x^3y-6x^5+5y^2)

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Jason solved the equation below. What error did he make?
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A school charges $6 for admission to a football game. The school has already sold 129 tickets x must be sold to earn at least $9
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5 0
3 years ago
A ball is kicked 4 feet above the ground with an initial vertical velocity of 55 feet per second. The function h(t)=−16t2+55t+4
kramer

<u>Given</u>:

A ball is kicked 4 feet above the ground with an initial vertical velocity of 55 feet per second.

The function h(t)=-16t^2+55t+4 represents the height h(in feet) of the ball after t seconds.

We need to determine the time of the ball at which it is 30 feet above the ground.

<u>Time:</u>

To determine the time that it takes for the ball to reach a height of 30 feet above the ground, let us substitute h(t) = 30, we get;

30=-16t^2+55t+4

26=-16t^2+55t

Adding both sides of the equation by 16t², we get;

16t^2+26=55t

Subtracting both sides of the equation by 55t, we have;

16t^2-55t+26=0

Let us solve the quadratic equation using the quadratic formula, we get;

t=\frac{-(-55) \pm \sqrt{(-55)^2-4(16)(26)}}{2(16)}

t=\frac{55 \pm \sqrt{3025-1664}}{32}

t=\frac{55 \pm \sqrt{1361}}{32}

t=\frac{55 \pm 36.89}{32}

t=\frac{55 + 36.89}{32} \ or \ t=\frac{55- 36.89}{32}

t=\frac{91.89}{32} \ or \ t=\frac{18.11}{32}

t=2.9 \ or \ t=0.6

The value of t is t = 0.6 because this denotes the time taken by the ball to reach a height of 30 feet from the ground.

Therefore, the time taken by the ball to reach a height of 30 feet above the ground is 0.6 seconds.

5 0
3 years ago
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