Just finished the test and the write answers are :
1) A,D,E
2)A,B
3)B,E
4) D
5) A
6) C
7) A
8) B
9) part A is C
Part B is A
Score 100%
Answer:
10 ft= 3 yd 1.000000 ft
Step-by-step explanation:
No explanation needed , it's a simple conversion.
1/16 of a pint because really there are 16 ounces in a one pint
Answer:
The sample mean is 13.
The sample variance is 0.2286.
The sample standard deviation is 0.4781.
Step-by-step explanation:
The sample is:
S = {12.6, 12.9, 13.4, 12.3, 13.6, 13.5, 12.6, 13.1}
The sample is of size <em>n</em> = 8.
The formula to compute the sample mean, sample variance and sample standard deviation are:


Compute the sample mean as follows:

The sample mean is 13.
Compute the sample variance as follows:
![s^{2}=\frac{1}{n-1}\sum (x-\bar x)^{2} \\=\frac{1}{8-1}[(12.6-13)^{2}+(12.9-13)^{2}+(13.4-13)^{2}+...+(13.1-13)^{2}] \\=\frac{1}{7}\times1.6\\=0.2286](https://tex.z-dn.net/?f=s%5E%7B2%7D%3D%5Cfrac%7B1%7D%7Bn-1%7D%5Csum%20%28x-%5Cbar%20x%29%5E%7B2%7D%20%5C%5C%3D%5Cfrac%7B1%7D%7B8-1%7D%5B%2812.6-13%29%5E%7B2%7D%2B%2812.9-13%29%5E%7B2%7D%2B%2813.4-13%29%5E%7B2%7D%2B...%2B%2813.1-13%29%5E%7B2%7D%5D%20%5C%5C%3D%5Cfrac%7B1%7D%7B7%7D%5Ctimes1.6%5C%5C%3D0.2286)
The sample variance is 0.2286.
Compute the sample standard deviation as follows:

The sample standard deviation is 0.4781.
Given expression:
for x = 3 and y = –2
(6) Mistake did by Grayson:
In second step, first to do 3² and then multiply with 4.
But Grayson first multiply 4 with 3 and then squared the expression.
This is wrong.
(7) Mistake did by Emily:
In third step, first to multiply 2 with (–2) using BODMAS rule and then add with 36.
But Emily first added 36 with 2 which gives 38.
This is wrong.
(8) Mistake did by Pat:
In first step, the y value given is –2.
But Pat substituted y value is 2.
This is wrong.
(9) Correct evaluation:



This is the correct way to evaluate the given expression.