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Arada [10]
3 years ago
13

Write an equation of the line that is parallel to y=1/2x+3 and passes through the point (10,-5)

Mathematics
2 answers:
Brut [27]3 years ago
8 0

Answer:

13

Step-by-step explanation:

                                                                   x    y

y=1/2x+3 and passes through the point (10,-5) 10 = x and -5 =y    1/2(10) - this mean times

-5 = 1/2(10) +3

1/2(10/1) = 1 x 10 and 2 x 1 = 10/2 = 5

-5 = 5 + 3 = 7

-5 = 7          + 5 + 7

+5  +5

= 13

(I wish You'll understand)

Leviafan [203]3 years ago
4 0
Y-(-5) = 1/2(x-10)

Y+5 = 1/2x -5

Y= 1/2x -10

Hope this helps!
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7 0
3 years ago
10 yards to 10 feet ratio
jarptica [38.1K]

Answer:

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Step-by-step explanation:

No explanation needed , it's a simple conversion.

6 0
3 years ago
How many pints equal an ounce
ch4aika [34]
1/16 of a pint because really there are 16 ounces in a one pint
5 0
3 years ago
Suppose that we have collected a sample of 8 observations with values 12.6, 12.9, 13.4, 12.3, 13.6, 13.5, 12.6, and 13.1. What a
Korolek [52]

Answer:

The sample mean is 13.

The sample variance is 0.2286.

The sample standard deviation is 0.4781.

Step-by-step explanation:

The sample is:

S = {12.6, 12.9, 13.4, 12.3, 13.6, 13.5, 12.6, 13.1}

The sample is of size <em>n</em> = 8.

The formula to compute the sample mean, sample variance and sample standard deviation are:

\bar x=\frac{1}{n} \sum x

s^{2}=\frac{1}{n}\sum (x-\bar x)^{2} \\s=\sqrt{\frac{1}{n}\sum (x-\bar x)^{2} }\\

Compute the sample mean as follows:

\bar x=\frac{1}{n} \sum x\\=\frac{1}{8}(12.6+ 12.9+ 13.4+ 12.3+ 13.6+ 13.5+ 12.6+ 13.1)\\=\frac{104}{8}\\ =13

The sample mean is 13.

Compute the sample variance as follows:

s^{2}=\frac{1}{n-1}\sum (x-\bar x)^{2} \\=\frac{1}{8-1}[(12.6-13)^{2}+(12.9-13)^{2}+(13.4-13)^{2}+...+(13.1-13)^{2}] \\=\frac{1}{7}\times1.6\\=0.2286

The sample variance is 0.2286.

Compute the sample standard deviation as follows:

s=\sqrt{s^{2}}\\=\sqrt{0.2286}\\=0.4781

The sample standard deviation is 0.4781.

4 0
3 years ago
PLZ HELP 6th grade math, problems attached
GREYUIT [131]

Given expression: 4 x^{2}+2 y for x = 3 and y = –2

(6) Mistake did by Grayson:

In second step, first to do 3² and then multiply with 4.

But Grayson first multiply 4 with 3 and then squared the expression.

This is wrong.

(7) Mistake did by Emily:

In third step, first to multiply 2 with (–2)  using BODMAS rule and then add with 36.

But Emily first added 36 with 2 which gives 38.

This is wrong.

(8) Mistake did by Pat:

In first step, the y value given is –2.

But Pat substituted y value is 2.

This is wrong.

(9) Correct evaluation:

4 x^{2}+2 y=4(3)^{2}+2(-2)

              =36+2(-2)

              =36+(-4)

             =32

This is the correct way to evaluate the given expression.

6 0
3 years ago
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