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ira [324]
2 years ago
6

What two numbers' sum=-4 and product=-2

Mathematics
1 answer:
n200080 [17]2 years ago
7 0

Let <em>a</em> and <em>b</em> be the two numbers. Then

<em>a</em> + <em>b</em> = -4

<em>a b</em> = -2

Solve the second equation for <em>b</em> :

<em>b</em> = -2/<em>a</em>

Substitute this into the first equation:

<em>a</em> - 2/<em>a</em> = -4

Multiply both sides by <em>a</em> :

<em>a</em>² - 2 = -4<em>a</em>

Move 4<em>a</em> to the left side:

<em>a</em>² + 4<em>a</em> - 2 = 0

Use the quadratic formula to solve for <em>a</em> :

<em>a</em> = (-4 ± √(4² - 4(-2))) / 2

<em>a</em> = -2 ± √6

If <em>a</em> = -2 + √6, then

-2 + √6 + <em>b</em> = -4

<em>b</em> = -2 - √6

In the other case, we end up with the same numbers, but <em>a</em> and <em>b</em> are swapped.

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11 months ago
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This one is moving up or down ....meaning moving horizontally........so the number is added outside the parenthesis. If it moves up then add(+)..........if it moves down then subtract(-). The formula used for horizontal shifts is, y=lXl + k
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Now,
It's a horizontal shift, so we can eliminate C and D.
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so the answer is B.
 lets check our answer by using the formula

Y = lxl + k
moves 2 units down so our k = (-2)
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6 0
2 years ago
Read 2 more answers
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Alex787 [66]

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5 0
3 years ago
2. The robot was initially placed at position (6,9), and at = 2 seconds, its position is (10,15).
qaws [65]
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4 0
3 years ago
Find the sum: 2 + 9 + 16 + ... + 37
iris [78.8K]

Step-by-step explanation:

Sum of arithmetic terms = n/2 × [2a + (n - 1)×d], where 'a' is the first term, 'd' is the common difference between two numbers, and 'n' is the number of terms.

this is the same as n/2 × (a1 + an), because

an = a1 + (n-1)×d

so, for the series above :

a or a1 = 2

d = 7, as every new term is the previous term plus 7.

for n

37 = a1 + (n-1)×d = 2 + (n-1)×7

and now solve for n

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so, the sum of all terms is

6/2 × (2+37) = 3×39 = 117

7 0
2 years ago
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