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ira [324]
3 years ago
6

What two numbers' sum=-4 and product=-2

Mathematics
1 answer:
n200080 [17]3 years ago
7 0

Let <em>a</em> and <em>b</em> be the two numbers. Then

<em>a</em> + <em>b</em> = -4

<em>a b</em> = -2

Solve the second equation for <em>b</em> :

<em>b</em> = -2/<em>a</em>

Substitute this into the first equation:

<em>a</em> - 2/<em>a</em> = -4

Multiply both sides by <em>a</em> :

<em>a</em>² - 2 = -4<em>a</em>

Move 4<em>a</em> to the left side:

<em>a</em>² + 4<em>a</em> - 2 = 0

Use the quadratic formula to solve for <em>a</em> :

<em>a</em> = (-4 ± √(4² - 4(-2))) / 2

<em>a</em> = -2 ± √6

If <em>a</em> = -2 + √6, then

-2 + √6 + <em>b</em> = -4

<em>b</em> = -2 - √6

In the other case, we end up with the same numbers, but <em>a</em> and <em>b</em> are swapped.

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set up and solve a system of equations to solve the problem The school band sells carnations on Valentine's Day for $3 each. It
sasho [114]

Answer:

Number of carnations = 6

Step-by-step explanation:

Let the number of carnations school band buys from florist be x.

Cost of each carnation = $0.50

Total cost for x number of carnations = $0.50x

Also , delivery cost = $15

So, total cost on buying x number of carnations from florist = 0.50x + 15

Now,

School band sells carnations at a price of $3 each.

Total revenue they get get after selling x number of carnations = $3x

We need to find that , when will the cost of the carnations be equal to the revenue from selling them.

i.e 3x = 0.50x + 15

or 3x - 0.50x = 15

or 2.50x = 15

or x = \frac{15}{2.50}

or x = 6

so on selling 6 carnations cost of carnation reach to the point where it is equal to revenue  


4 0
3 years ago
Line segment AB has endpoints A(3, -7) and B(-9,-5). Find the equation of the perpendicular bisector
kupik [55]

Answer:

y = 6x + 12

Step-by-step explanation:

We require the midpoint M and slope of AB

Using the midpoint formula, then

M = [ \frac{1}{2} (3 - 9) , \frac{1}{2} (- 7 - 5) ] = (- 3, - 6 )

Calculate the slope m using the slope formula

m = \frac{y_{2}-y_{1}  }{x_{2}-x_{1}  }

with (x₁, y₁ ) = A(3, - 7) and (x₂, y₂ ) = B(- 9, - 5)

m = \frac{-5+7}{-9-3} = \frac{2}{-12} = - \frac{1}{6}

Given a line with slope m then the slope of a line perpendicular to it is

m_{perpendicular} = - \frac{1}{m} = - \frac{1}{-\frac{1}{6} } = 6

The equation of a line in slope- intercept form is

y = mx + c ( m is the slope and c the y- intercept )

Here m = 6 , thus

y = 6x + c ← is the partial equation

To find c substitute M(- 3, - 6) into the partial equation

- 6 = - 18 + c ⇒ c = - 6 + 18 = 12

y = 6x + 12 ← equation of perpendicular bisector

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3 years ago
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