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Helen [10]
3 years ago
5

An investment firm wants to create a billboard that displays an enlarged $1,000,000 bill. The actual size of the bill is 2.61 in

ches by 6.14 inches. If the billboard is 48 feet wide, what's the scale of the bill to the billboard? A. 1′ = 8.71″ B. 1′ = 7.81″ C. 1″ = 8.71′ D. 1″ = 7.81′
Mathematics
1 answer:
Mandarinka [93]3 years ago
3 0

We know how wide the billboard will be. Therefore, to know how much the original image should be enlarged, you must divide the final width of the billboard between the current width of the invoice.

We know both data, then we perform the operation:

48 feet /6.14 inches = 7.81 feet / inches .


Therefore the correct answer is option D. 1″ = 7.81′

For the bill to cover the billboard, the bill must be expanded by a factor of 7.81 feet long per inch long that has the original image.

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Nick types 275 words in 2.5 minutes. At this rate, how many hours would it take for him to type 9900 words?
ioda
3/5 of an hour (0.6 hours)



First, find how many words Nick types in an hour by multiplying 275 * 60.

Nick types 16,500 words per hour.

Now just divide 9,900 by 16,500.

It takes Nick 3/5 of an hour to type 9,900 words. (0.6 hours)



Please consider marking this answer as Brainliest to help me advance.

5 0
3 years ago
Can anyone help me with the rest of my ixl m.1 please and thank you
mina [271]

Answer:

u=54

Step-by-step explanation:

VX is middle line of triangle, so

VX=ZY/2.....(1)

We know that

Zy=u

Vx=u-27

Put that in (1) we have:

u-27=u/2

2u-54=u

2u-u=54

u=54

5 0
2 years ago
Find the vertex and length of the latus rectum for the parabola. y=1/6(x-8)^2+6
Ivan

Step-by-step explanation:

If the parabola has the form

y = a(x - h)^2 + k (vertex form)

then its vertex is located at the point (h, k). Therefore, the vertex of the parabola

y = \dfrac{1}{6}(x - 8)^2 + 6

is located at the point (8, 6).

To find the length of the parabola's latus rectum, we need to find its focal length <em>f</em>. Luckily, since our equation is in vertex form, we can easily find from the focus (or focal point) coordinate, which is

\text{focus} = (h, k +\frac{1}{4a})

where \frac{1}{4a} is called the focal length or distance of the focus from the vertex. So from our equation, we can see that the focal length <em>f</em> is

f = \dfrac{1}{4(\frac{1}{6})} = \dfrac{3}{2}

By definition, the length of the latus rectum is four times the focal length so therefore, its value is

\text{latus rectum} = 4\left(\dfrac{3}{2}\right) = 6

5 0
3 years ago
ariana takes a handful of cookies and divides them evenly between her 3 kids. then she grabs one more cookie for each kid. if ea
Virty [35]

Answer:

9 cookies in her original handful

Step-by-step explanation:

3 times 4 equals 12

12-3=9

4 0
2 years ago
Given that f.x 3x-2 over x+1 g[x] x +5 evaluate f[-4] and gf [-2]
Jobisdone [24]

The value of f[ -4 ] and g°f[-2] are \frac{14}{3} and 13 respectively.

<h3>What is the value of f[-4] and g°f[-2]?</h3>

Given the function;

  • f(x) = \frac{3x-2}{x+1}
  • g(x)=x+5
  • f[ -4 ] = ?
  • g°f[ -2 ] = ?

For f[ -4 ], we substitute -4 for every variable x in the function.

f(x) = \frac{3x-2}{x+1}\\\\f(-4) = \frac{3(-4)-2}{(-4)+1}\\\\f(-4) = \frac{-12-2}{-4+1}\\\\f(-4) = \frac{-14}{-3}\\\\f(-4) = \frac{14}{3}

For g°f[-2]

g°f[-2] is expressed as g(f(-2))

g(\frac{3x-2}{x+1}) =  (\frac{3x-2}{x+1}) + 5\\\\g(\frac{3x-2}{x+1}) =  \frac{3x-2}{x+1} + \frac{5(x+1)}{x+1}\\\\g(\frac{3x-2}{x+1}) =  \frac{3x-2+5(x+1)}{x+1}\\\\g(\frac{3x-2}{x+1}) =  \frac{8x+3}{x+1}\\\\We\ substitute \ in \ [-2] \\\\g(\frac{3x-2}{x+1}) =  \frac{8(-2)+3}{(-2)+1}\\\\g(\frac{3x-2}{x+1}) =  \frac{-16+3}{-2+1}\\\\g(\frac{3x-2}{x+1}) =  \frac{-13}{-1}\\\\g(\frac{3x-2}{x+1}) =  13

Therefore, the value of f[ -4 ] and g°f[-2] are \frac{14}{3} and 13 respectively.

Learn more about composite functions here: brainly.com/question/20379727

#SPJ1

6 0
1 year ago
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