P=2L+2W find the width of a rectangle whose length is 35 and perimeter is 82in

Mathematics

1 answer:

mart [117]3 years ago

7 0

Answer:

Step-by-step explanation:

We can fill in what we know which is the length and perimeter.

82=2(35)+2(w)

Multiply 35 x 2 = 70

82-70= 12

12/2=6

You might be interested in

given the points a (-1,2) and (7,14), find the coordinates of the point p on directed line segment ab that partitions ab in the

Vinvika [58]

Check the picture below.

$\bf \left. \qquad \right.\textit{internal division of a line segment}
\\\\\\
a(-1,2)\qquad b(7,14)\qquad
\qquad 1:3
\\\\\\
\cfrac{aP}{Pb} = \cfrac{1}{3}\implies \cfrac{a}{b} = \cfrac{1}{3}\implies 3a=1b\implies 3(-1,2)=1(7,14)
\\\\
-------------------------------\\\\
{ P=\left(\cfrac{\textit{sum of "x" values}}{r1+r2}\quad ,\quad \cfrac{\textit{sum of "y" values}}{r1+r2}\right)}$

$\bf -------------------------------\\\\
P=\left(\cfrac{(3\cdot -1)+(1\cdot 7)}{1+3}\quad ,\quad \cfrac{(3\cdot 2)+(1\cdot 14)}{1+3}\right)
\\\\\\
P=\left( \cfrac{-3+7}{4}~,~\cfrac{6+14}{4} \right)$