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4 years ago

Could someone help me find this?

Mathematics

2 answers:

german4 years ago

6 0

Answer: y = 7x²

<u>Step-by-step explanation:</u>

The general form of a quadratic equation is: y = a(x - h)² + k where

"a" represents the vertical stretch
"h" represents the shift to the left (or right)
"k" represents the shift up (or down)
(h, k) represents the vertex

Given the parent function y = x², a vertical stretch by a factor of 7 means the a-value is 7 ⇒ y = 7x²

OLEGan [10]4 years ago

6 0

Answer:

The scale value is essentially the ratio between the the y-value of the scaled parabola to the y-value of the original parabola at a given x-valu

Step-by-step explanation:

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A newsletter publisher believes that less than 49% of their readers own a laptop. For marketing purposes, a potential advertiser

Zepler [3.9K]

Answer:

The answer is "At the 0,10 level, there should be enough proof that the percentage is below 49%"

Step-by-step explanation:

Null and alternative hypothesis:

$H_0 :P \geq 0.49\\\\H_1:P$

Significance level: $\alpha = 0.10$

It is decided that the null hypothesis at the defined meaning level is rejected.

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3 years ago

A researcher investigating whether joggers are less likely to get colds than people who

STatiana [176]

Your answer is b bro

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3 years ago

3[–x + (2 x + 1)] = x – 1

photoshop1234 [79]

Answer:

Step-by-step explanation:

$3[-x + (2 x + 1)] = x -1\\\\\mathrm{Expand\:}3\left(-x+\left(2x+1\right)\right):\quad 3x+3\\3x+3=x-1\\$

Collect like terms

$3x -x =-1-3$

Add similar elements

$2x = -4\\\\\mathrm{Divide\:both\:sides\:by\:}2\\\frac{2x}{2}=\frac{-4}{2}\\\\Simplify\\\\x = -2$

3 0

3 years ago

PLEASE HELP I NEED THIS ASAP<br> Find the vertex of y=x^2-7x+4

Goshia [24]

Answer:

$\mathrm{Minimum}\space\left(\frac{7}{2},\:-\frac{33}{4}\right)$

Step-by-step explanation:

$y=x^2-7x+4\\\mathrm{The\:vertex\:of\:an\:up-down\:facing\:parabola\:of\:the\:form}\:y=ax^2+bx+c\:\mathrm{is}\:x_v=-\frac{b}{2a}\\\mathrm{The\:parabola\:params\:are:}\\a=1,\:b=-7,\:c=4\\x_v=-\frac{b}{2a}\\x_v=-\frac{\left(-7\right)}{2\cdot \:1}\\\mathrm{Simplify}\\x_v=\frac{7}{2}\\\mathrm{Plug\:in}\:\:x_v=\frac{7}{2}\:\mathrm{to\:find\:the}\:y_v\:\mathrm{value}\\y_v=\left(\frac{7}{2}\right)^2-7\cdot \frac{7}{2}+4\\$

$\mathrm{Simplify\:}\left(\frac{7}{2}\right)^2-7\cdot \frac{7}{2}+4:\quad -\frac{33}{4}\\y_v=-\frac{33}{4}\\Therefore\:the\:parabola\:vertex\:is\\\left(\frac{7}{2},\:-\frac{33}{4}\right)\\\mathrm{If}\:a0,\:\mathrm{then\:the\:vertex\:is\:a\:minimum\:value}\\a=1\\\mathrm{Minimum}\space\left(\frac{7}{2},\:-\frac{33}{4}\right)$

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4 years ago

a car starts from rest and travels for 5.0s with a uniform acceleration of 1.5 m/s^2. what is the final velocity of the car? how

AfilCa [17]

V = u + at
u = 0
v = 0 + 1.5*5
v = 7.5 m/s
final velocity is 7.5 m/s

s = ut + 0.5at^2
s = 0 + (0.5*1.5*5^2)
s = (0.5*1.5*25)
s = 18.75 m
total travel distance is 18.75 m.

5 0

4 years ago