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3 years ago

Carla bought 66 inches of pink ribbon and 36 inches of white ribbon. She wanted to cut each ribbon into 6 equal pieces.

Mathematics

2 answers:

Mashcka [7]3 years ago

8 0

Answer:

Step-by-step explanation:

A is correct because each ribbon needs to be split into 6 pieces, meaning you have to divide by 6. Do that for both. Then you subtract the quotients because it is asking for the difference.

laila [671]3 years ago

7 0

Answer: A.

Step 1. Divide 66 ÷ 6

Step 2. Divide 36 ÷ 6

Step 3. Subtract the two quotients.

Step-by-step explanation:

Since Carla wants to cut each ribbon into six equal pieces, each pink ribbon piece is going to make up 1/6 of the original 66 inches of pink ribbon. 66 × 1/6 is equivalent to 66 ÷ 6. For the white ribbon, each piece is going to make up 1/6 of the original 36 inches of white ribbon. 36 × 1/6 is equivalent to 36 ÷ 1/6. The word “difference“ means to subtract, therefore we need to subtract the two quotients. (The answer would be 5 since 11 - 6 = 5)

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Find the dimensions of the open rectangular box of maximum volume that can be made from a sheet of cardboard 21 in. by 12 in. by

a_sh-v [17]

Answer:

Dimension of the box is $16.1\times 7.1\times 2.45$

The volume of the box is 280.05 in³.

Step-by-step explanation:

Given : The open rectangular box of maximum volume that can be made from a sheet of cardboard 21 in. by 12 in. by cutting congruent squares from the corners and folding up the sides.

To find : The dimensions and the volume of the box?

Solution :

Let h be the height of the box which is the side length of a corner square.

According to question,

A sheet of cardboard 21 in. by 12 in. by cutting congruent squares from the corners and folding up the sides.

The length of the box is $L=21-2h$

The width of the box is $W=12-2h$

The volume of the box is $V=L\times W\times H$

$V=(21-2h)\times (12-2h)\times h$

$V=(21-2h)\times (12h-2h^2)$

$V=252h-42h^2-24h^2+4h^3$

$V=4h^3-66h^2+252h$

To maximize the volume we find derivative of volume and put it to zero.

$V'=12h^2-132h+252$

$0=12h^2-132h+252$

Solving by quadratic formula,

$h=\frac{-b\pm\sqrt{b^2-4ac}}{2a}$

$h=\frac{-(-132)\pm\sqrt{132^2-4(12)(252)}}{2(12)}$

$h=\frac{132\pm72.99}{24}$

$h=2.45,8.54$

Now, substitute the value of h in the volume,

$V=4h^3-66h^2+252h$

When, h=2.45

$V=4(2.45)^3-66(2.45)^2+252(2.45)$

$V\approx 280.05$

When, h=8.54

$V=4(8.54)^3-66(8.54)^2+252(8.54)$

$V\approx -170.06$

Rejecting the negative volume as it is not possible.

Therefore, The volume of the box is 280.05 in³.

The dimension of the box is

The height of the box is h=2.45

The length of the box is $L=21-2(2.45)=16.1$

The width of the box is $W=12-2(2.45)=7.1$

So, Dimension of the box is $16.1\times 7.1\times 2.45$

6 0

4 years ago

What's 28=4 times m m = what

Ratling [72]

Answer:

28 = 4m

28/4 = m

7 = m

m = 7

Hope this helps

5 0

4 years ago

Read 2 more answers

Help please! show work thanks

Andre45 [30]

Answers
b = 2.77 m
A = 43.0°
C = 111.1°

cosine law to find b

$b^2 = a^2 + c^2 -2ac \cos B \\ \\
b = \sqrt{a^2 + c^2 -2ac \cos B} \\ \\
b = \sqrt{4.33^2 + 5.92^2 - 2(4.33)(5.92) \cos 25.9} \\
b = 2.7708\ m$

b = 2.7708\ m

Find angle A with sine law

$\displaystyle
\frac{\sin A}{a} = \frac{\sin B}{b} \\ \\
\sin A = \frac{a \sin B}{b} \\ \\
A = \sin^{-1} \left[ \frac{a \sin B}{b} \right] \\ \\
A = \sin^{-1} \left[ \frac{4.33 \sin 25.9}{2.7708} \right] \\ \\
A = 43.0467020$

Find C with angles in triangle sum to 180

A + B + C = 180
C = 180 - A - B
C = 180 - 43.0467020 - 25.9
C = 111.1

6 0

4 years ago

Find the negation of statement <br>2+5=5

chubhunter [2.5K]

Answer:

Can u mark brainelst plz?

Step-by-step explanation:

x − 1 > 5

x > − 6

x + 1 ≥ 9

7 0

3 years ago