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natita [175]
3 years ago
15

curve before applying the theorem.)F(x, y) = y cos(x) − xy sin(x), xy + x cos(x), C is the triangle from (0, 0) to (0, 12) to (3

, 0) to (0, 0)
Mathematics
1 answer:
Serhud [2]3 years ago
4 0

C has a clockwise orientation, so in order to use Green's theorem (which is probably the "theorem" mentioned here), we have

\displaystyle\int_C\vec F\cdot\mathrm d\vec r=-\iint_D\frac{\partial(xy+x\cos x)}{\partial x}-\frac{\partial(y\cos x-xy\sin x)}{\partial y}\,\mathrm dx\,\mathrm dy

where D is the triangle region.

=\displaystyle\int_0^3\int_0^{12-4x}(\cos x-x\sin x)-(y+(\cos x-x\sin x))\,\mathrm dy\,\mathrm dx

=\displaystyle-\int_0^3\int_0^{12-4x}y\,\mathrm dy\,\mathrm dx=\boxed{-72}

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Step-by-step explanation:

3 0
3 years ago
See the ​attached file.
Masja [62]

f(x) = 4x - x^2

1)

f(4) = 4(4) - 4^2 = 16 - 16 = 0

f(-4) = 4(-4) - (-4)^2 = -16 - 16 = -32

f(4) - f(-4) = 0 - (-32) = 32

2)

f(3/2) = 4(3/2) - (3/2)^2

f(3/2) = 6 - 9/4 = 15/4

√f(3/2) = √(15/4) = √15 / 2

3)

f(x + h) = 4(x + h) - (x + h)^2

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= 4x + 4h -x^2 - 2xh - h^2

f(x - h) = 4(x - h) - (x - h)^2

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So

[f(x + h) -f(x - h) ] / 2h

= [4x + 4h -x^2 - 2xh - h^2 - ( 4x - 4h -x^2 + 2xh - h^2 )] / 2h

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3 0
3 years ago
Pls help me asap important assessment
oksian1 [2.3K]

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Step-by-step explanation:

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the correct working

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7 0
2 years ago
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Dima020 [189]
Supplementary angles add up to 180 degrees
ratio of 1:4.....added = 5

1/5(180) = 180/5 = 36 <=== smaller angle
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4 0
3 years ago
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