JK, KL, and JL are all tangent to circle O. JA = 3, JL = 7, and the perimeter of triangle JKL = 26. What Are JK and KL?

Mathematics

1 answer:

sattari [20]3 years ago

4 0

Answer is B) JK=9 and KL=10

you subtract 7 from 26 to get 19

You might be interested in

Which expression is equivalent to the expression 6(-2n + 7) - 3(5n + 9)?

timurjin [86]

-27n+15 is your answer

3 0

3 years ago

P and q are points on the line 2y-5x=10

schepotkina [342]

Answer:

$2y-5x =10\\when \ x = 0, \ 2y = 10 => y = 5\\\\\\when \ y = 0, -5x =10 => x =-2\\\\Therefore \ the \ coordinates \ of \ the \ points \ p \ and \ q\ are \ (0, 2) \ and \ (-2, 0)$

7 0

3 years ago

Please help me its due tonight!!!

Bumek [7]

Answer:

The initial cost is $20, and it adds $5per hour

Step-by-step explanation:

Read the graph

3 0

3 years ago

Read 2 more answers

If f(x) = 3x – 12, what is f(2)?

fredd [130]

It would be B. -6.

f(x) = 3x-12
f(2) = 3(2)-12
f(2) = 6-12
f(2) = -6

5 0

3 years ago

Read 2 more answers

X to the 2 power -6 when X = -14

riadik2000 [5.3K]

-14x-14 = 196 then subtract -6 from 196 because they'll cancel each other out. the answer is 190.

8 0

3 years ago